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Answer:
- m = 1,000/58.5
- b = - 1,000 / 58.5
1) Variables
- molarity: M
- density of the solution: d
- moles of NaCl: n₁
- mass of NaCl: m₁
- molar mass of NaCl: MM₁
- total volume in liters: Vt
- Volume of water in mililiters: V₂
- mass of water: m₂
2) Density of the solution: mass in grams / volume in mililiters
3) Mass of NaCl: m₁
Number of moles = mass in grams / molar mass
⇒ mass in grams = number of moles × molar mass
m₁ = n₁ × MM₁
4) Number of moles of NaCl: n₁
Molarity = number of moles / Volume of solution in liters
M = n₁ / Vt
⇒ n₁ = M × Vt
5) Substitue in the equation of m₁:
m₁ = M × Vt × MM₁
6) Substitute in the equation of density:
d = [M × Vt × MM₁ + m₂] / (1000Vt)
7) Simplify and solve for M
- d = M × Vt × MM₁ / (1000Vt) + m₂/ (1000Vt)
- d = M × MM₁ / (1000) + m₂/ (1000Vt)
Making the simplistic assumption that the dissolved NaCl(s) does not affect the volume of the solvent water means 1000Vt = V₂
- d = M × MM₁ / (1000) + m₂/ V₂
m₂/ V₂ is the density of water: 1.00 g/mL
- d = M × MM₁ / (1000) + 1.00 g/mL
- M × MM₁ / (1000) = d - 1.00 g/mL
- M = [1,000/MM₁] d - 1,000/ MM₁
8) Substituting MM₁ = 58.5 g/mol
- M = [1,000/58.5] d - [1,000/ 58.5]
Comparing with the equation Molarity = m×density + b, you obtain:
- m = 1,000/58.5
- b = - 1,000/58.5
Answer:
Percent yield = 69.4%
Explanation:
Given data:
Percent yield = ?
Actual yield of copper = 4.65 g
Mass of aluminium = 1.87 g
Mass of copper sulfate = excess
Solution:
Chemical equation:
2Al + 3CuSO₄ → Al₂(SO₄)₃ + 3Cu
Number of moles of Aluminium:
Number of moles = mass/ molar mass
Number of moles = 1.87 g/27 g/mol
Number of moles = 0.07 mol
Now we will compare the moles of Al with copper.
Al : Cu
2 : 3
0.07 : 3/2×0.07 =0.105 mol
Mass of Copper:(Theoretical yield)
Mass = Number of moles × molar mass
Mass = 0.105 mol × 63.5 g/mol
Mass = 6.7 g
Percent yield:
Percent yield = Actual yield / theoretical yield × 100
Percent yield = 4.65 g/ 6.7 g × 100
Percent yield = 69.4%
True. Because they are white we know that they reflect light, and thus heat.
Explanation:
Electromagnetic wave Wavelength
(1) Microwave = 1 m to 1 mm =
to 
(2) Ultraviolet = 10 nm to 400 nm
(3) Radio waves = 1 mm to 100 km =
to 
(4) Infrared = 700 nm to 1 mm
(5) X-ray = 0.01 nm to 10 nm
(6) Visible = 400 nm t0 700 nm
a) In order of increasing wavelength:
: 5 < 2 < 6 < 4 < 1 < 3
b) Frequency of the electromagnetic wave given as:

= frequency
= Wavelength
c = speed of light

So, the increasing order of frequency:
: 3 < 1 < 4 < 6 < 2 < 5
c) Energy(E) of the electromagnetic wave is given by Planck's equation :


So, the increasing order of energy:
: 3 < 1 < 4 < 6 < 2 < 5