Question

The electric force between objects A and B is F. If the charge of object A were twice as large as it is, but everything else was kept the same, what would be the new electric force between objects A and B?

Answer 1

Answer:

$F'=2F$

Explanation:

According to Coulomb's law and assuming the objects as point charges, the magnitude of the electric force that each object exerts on the other is defined as:

$F=\frac{kq_Aq_B}{d^2}$

Here k is thee Coulomb constant, $q_A$ and $q_B$ are the charges of the objects and d is the distance of separation between them. We have $q'_A=2q_A$:

$F'=\frac{kq'_Aq_B}{d^2}\\F'=\frac{k2q_Aq_B}{d^2}\\F'=2\frac{kq_Aq_B}{d^2}\\F'=2F$