<h3>
Answer:</h3>
46.67 m/s²
<h3>
Explanation:</h3>
<u>We are given;</u>
- Mass of a rocket = 3 kg
- Force applied = 140 N
we are supposed to calculate the acceleration of the rocket;
- We are going to use the second Newton's law of motion;
- According to Newton's second Law of motion force is equivalent to the product of mass and acceleration.
- This is from the fact that the resultant force and the rate of change in linear momentum are directly proportional.
Therefore;
F = Ma
In this case;
Rearranging the formula
a = F ÷ m
= 140 N ÷ 3 kg
= 46.67 m/s²
Thus, the acceleration of the rocket is 46.67 m/s²
i think its a, good luck on your test
Answer:
D
Explanation:
Kinetic energy = 1/2mV^2
From the formula above, we can deduce that kinetic energy is proportional to the square of speed. That is,
K.E = V^2
Graphically, the relationship isn't linear but a positive exponential. Therefore, option D is the correct answer.
Answer:329.72 N
Explanation:
Given
mass of ball
velocity of ball
glove recoil distance
Energy associated with ball E=kinetic energy of ball
Now if an average for is applied to stop the ball then work done by this force is equal to kinetic energy of the ball
Answer:
Workdone = 20 Joules
Explanation:
Given the following data;
Force = 10N
Extension, e = 4cm to meters = 4/100 = 0.04 meters
Workdone extension = 40cm to meters = 40/100 = 0.4 meters
To find the work done;
First of all, we would find the spring constant using the formula;
Force = spring constant * extension
10 = spring constant * 0.04
Spring constant = 10/0.04
Spring constant = 250 N/m
Next, we find the work done;
Workdone = ½ke²
Where;
k is the spring constant.
e is the extension.
Substituting into the formula, we have;
Workdone = ½ * 250 * 0.4²
Workdone = 125 * 0.16
Workdone = 20 Joules