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gtnhenbr [62]
3 years ago
12

There is an attachment for my question relating to geometry...thank you for the help

Mathematics
2 answers:
timurjin [86]3 years ago
8 0
The answer to Part A is C. Both x and y are negative and the answer to Part B. is A. Both are postive
Tomtit [17]3 years ago
6 0
Hello I hope this helps. I'm pretty sure this is the answer.
 
Part A: C
Part B: A


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Suppose a population of honey bees in Ephraim, UT has an initial population of 2300 and 12 years later the population reaches 13
Rama09 [41]

Answer:

common ratio: 1.155

rate of growth: 15.5 %

Step-by-step explanation:

The model for exponential growth of population P looks like: P(t)=P_i(1+r)^t

where P(t) is the population at time "t",

P_i is the initial (starting) population

(1+r) is the common ratio,

and r is the rate of growth

Therefore, in our case we can replace specific values in this expression (including population after 12 years, and  initial population), and solve for the unknown common ratio and its related rate of growth:

P(t)=P_i(1+r)^t\\13000=2300*(1+r)^{12}\\\frac{13000}{2300} = (1+r)^12\\\frac{130}{23} = (1+r)^{12}\\1+r=\sqrt[12]{\frac{130}{23} } =1.155273\\

This (1+r) is the common ratio, that we are asked to round to the nearest thousandth, so we use: 1.155

We are also asked to find the rate of increase (r), and to express it in percent form. Therefore we use the last equation shown above to solve for "r" and express tin percent form:

1+r=1.155273\\r=1.155273-1=0.155273

So, this number in percent form (and rounded to the nearest tenth as requested) is: 15.5 %

6 0
2 years ago
What is 32% of 4 because I don't know if I doing my calculations right?
GuDViN [60]

Answer:

1.28

Step-by-step explanation:

32% of 4

0.32 × 4

1.28

6 0
3 years ago
Read 2 more answers
(6+3)+21=6+(3+21) name each property of addition or multiplication
Anna007 [38]
(6 + 3) + 21 = 6 + (3 + 21)

It's an ASSOCIATIVE PROPERTY
(a + b) + c = a + (b + c)
7 0
3 years ago
Solve this application problem using a system of equations: The Bright College footballteam scored 80 times last season, some on
Goryan [66]

Answer:

\large \boxed{\sf \ \ 69 \ \textbf{touchdowns } 11 \ \textbf{field goals } \ }

Step-by-step explanation:

Hello,

Touchdown is 7 points, field goals is 3 points

Let's note a the number of touchdowns and b the number of field goals, we can write

   (1)    a + b = 80

   (2)    7a + 3b = 516

(2) - 3*(1) gives

7a + 3b - 3(a + b) = 516 - 3*80

<=> 7a + 3b -3a - 3b = 516 - 240 = 276

<=> 4a = 276

<=> a=\dfrac{276}{4}=69

And then from (1) b = 80 - 69 = 11

Hope this helps

4 0
3 years ago
How do I solve this question?
Juli2301 [7.4K]

11 because if you count the spaces between the two places, the answer would be 11.

3 0
3 years ago
Read 2 more answers
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