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2 years ago

Center and the radius please!

Mathematics

1 answer:

Aleks04 [339]2 years ago

8 0

Center is (9,-4) the radius is the square root of 73

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For what values of x is -1/2x+6>4x-3

borishaifa [10]

Answer:

x<2

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

8 0

3 years ago

Which ordered pairs are solutions to the inequality y−2x≤−3?

My name is Ann [436]

we will proceed to resolve each case to determine the solution

we have

$y-2x \leq -3$

$y\leq2x-3$

we know that

If an ordered pair is the solution of the inequality, then it must satisfy the inequality.

case a) $(5,-3)$

Substitute the value of x and y in the inequality

$-3\leq2*5-3$

$-3\leq7$ -------> is true

The ordered pair $(5,-3)$ is a solution

case b) $(0,-2)$

Substitute the value of x and y in the inequality

$-2\leq2*0-3$

$-2\leq-3$ -------> is False

The ordered pair $(0,-2)$ is not a solution

case c) $(-6,-3)$

Substitute the value of x and y in the inequality

$-3\leq2*-6-3$

$-3\leq-15$ -------> is False

The ordered pair $(-6,-3)$ is not a solution

case d) $(1,-1)$

Substitute the value of x and y in the inequality

$-1\leq2*1-3$

$-1\leq-1$ -------> is True

The ordered pair $(1,-1)$ is a solution

case e) $(7,12)$

Substitute the value of x and y in the inequality

$12\leq2*7-3$

$12\leq11$ -------> is False

The ordered pair $(7,12)$ is not a solution

Verify

using a graphing tool

see the attached figure

the solution is the shaded area below the line

The points A and D lies on the shaded area, therefore the ordered pairs A and D are solution of the inequality

6 0

3 years ago

Read 2 more answers

A circle with a radius of 10 inches is placed inside a square with a side length of 20 inches. Find the area of the square.

NikAS [45]

I think the answer is A , if y’all don’t get it right I’m sorry

4 0

3 years ago

Read 2 more answers

if the mean of A and B is 20 the mean of B and C is 24 and the mean of A,B and C is 18 .what is the mean of A and C

gizmo_the_mogwai [7]

Answer:

Step-by-step explanation:

5 0

3 years ago

Which of these correctly rearranges the terms in this polynomial so like terms are next to each other?3 – 6x + 4x2 + 3x – 6x2 –

fomenos

Answer:

The rearrangement of the terms is $4x^2-6x^2-6x+3x+3-4$ .

Step-by-step explanation:

The given expression is

$3-6x+4x^2+3x-6x^2-4$

Two terms are called like terms if they have same variables having same degree.

In the given expression 3 and -4, -6x and 3x, 4x² and -6x² are like terms.

Arrange the given terms according to their degree and arrange in this way so like terms are next to each other.

$4x^2-6x^2-6x+3x+3-4$

Therefore the rearrangement of the terms is $4x^2-6x^2-6x+3x+3-4$ .

7 0

3 years ago