Answer:
1.274 moles
Explanation:
The equation for the reaction can be represented as follows:
⇄ 
+ 
K = 0.060
K = ![\frac{[PCl_3][Cl_2]}{[PCl_5]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BPCl_3%5D%5BCl_2%5D%7D%7B%5BPCl_5%5D%7D)
Concentration of = 
Concentration of = 
Concentration of = 0.398 moles
If we construct an ICE table for the above equation; we have:
⇄ +
Initial 0.398 0 0
Change - x + x + x
Equilibrium (0.398 - x) x x
K =
K = ![\frac{[x][x]}{[0.398-x]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Bx%5D%5Bx%5D%7D%7B%5B0.398-x%5D%7D)
K = 
0.060 =
0.06(0.398-x) = x²
0.02388 - 0.060x = x²
x² + 0.060x - 0.02388 = 0 (quadratic equation)
a = 1; b= 0.06; c= -0.02388
Using quadratic formula;
= 
= 
= 
= 
= 
= 
or 
= 
or 
= 0.1274 or -0.1874
We go by the positive value which says:
[x] = 0.1274 M
number of moles = 0.1274 × 10.0
= 1.274 moles
∴ the number of moles of Cl₂ produced at equilibrium = 1.274 moles
1. At constant tempaerature and pressure, 3 tablets produce 600cm^3 of gas
Thus calculating for 1 tablet that produces 600 / 3 = 200 cm^3
So now two tablets produce 200 x 2 = 400 cm^3
2. We have the equation PV = nRT, n being the number of moles
Pressure P = 1,000 kPa
Volume V = 3 L
R = 8.31 L kPa/mol-K
Temperature T = 298 K
n = PV / RT = (1000 x 3) / (8.31 x 298) = 3000 / 2476.38 = 1.21 moles
Number of moles = 1.21 moles.
Answer: 39.948 grams
Explanation:
The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles Ar, or 39.948 grams
Answer:
S₂O₂
Explanation:
The multiplying prefix di- means "two."
Thus, a molecule of disulfur dioxide has two atoms of sulfur and two atoms of oxygen.
The formula is S₂O₂.
Answer:
1)The molar mass of an atom is simply the mass of one mole of identical atoms. However, most of the chemical elements are found on earth not as one isotope but as a mixture of isotopes, so the atoms of one element do not all have the same mass.
2)Equally important is the fact that one mole of a substance has a mass in grams numerically equal to the formula weight of that substance. Thus, one mole of an element has a mass in grams equal to the atomic weight of that element and contains 6.02 X 1023 atoms of the element.
