Answer:
Anne is the best hitter as she has the best hitting average of 0.406
Step-by-step explanation:
Anne hits 65 bases out of 160 at - bats.
Beth's betting average = 0.399
Collin's hit = 40%
Now, we need to convert all the three hitting rates into same parameters to compare them with each other.
Average hit rate of Anne = ![\frac{\textrm{Total numberof base}}{\textrm{Total number of at - bats}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctextrm%7BTotal%20numberof%20base%7D%7D%7B%5Ctextrm%7BTotal%20number%20of%20%20at%20-%20bats%7D%7D)
![= \frac{65}{160} = 0.406](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B65%7D%7B160%7D%20%20%3D%200.406)
⇒The betting average of Anne = 0.406
Now, The hit - rate of Collin = 40%
Converting the percentage rate into decimal, we get the hit rate of Collin
= ![\frac{40}{100} = 0.40](https://tex.z-dn.net/?f=%5Cfrac%7B40%7D%7B100%7D%20%20%3D%200.40)
Hence, we get that Hitting Average of :
<u>Anne = 0.406</u>, Beth = 0.3999 and Collin = 0.400
Hence, from the above data Anne is the best hitter as she has the best hitting average of 0.406.