Question

What is the magnitude of the magnetic field created 4.0m away from a 10.0 A current?

Answer 1

Answer:

The magnitude of the magnetic field created is 5 x 10⁻⁷ T

Explanation:

Given;

magnitude of current, I = 10.0 A

distance of the magnetic field, r = 4.0m

Apply Biot-Savart Law to determine the magnitude of of the magnetic field created;

$B = \frac{\mu_oI}{2 \pi r}$

where;

B is the magnitude of of the magnetic field

μ₀ is constant

I is current

r is the distance of the field

$B = \frac{4 \pi*10^{-7} *10}{2 \pi*4} = 5*10^{-7} \ T$

Therefore, the magnitude of the magnetic field created is 5 x 10⁻⁷ T