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vagabundo [1.1K]
3 years ago
11

Can you help me answer this?

Physics
1 answer:
Pavel [41]3 years ago
5 0
The answer is D. If you aren't consistent with your drop positions, then your data may be invalid. To be frank: it basically screws over the experiment.
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A long wire carrying I=1.1A of constant current oriented North-to-South (and the current is running northwards) is placed horizo
Tema [17]

Answer:

The absolute value of the angular deviation is 39.3°.

Explanation:

Given that,

Current = 1.1 A

Distance = 0.9 cm

Magnetic field = 20μT

We need to calculate the magnetic field due to wire

Using formula of magnetic field

B=\dfrac{\mu_{0}I}{2\pi d}

Put the value into the formula

B=\dfrac{4\pi\times10^{-7}\times1.1}{2\pi\times0.9\times10^{-2}}

B=24.4\times10^{-6}\ T

B=24.4\ \mu T

We need to calculate the absolute value of the angular deviation

Using formula of direction

\theta=\tan^{-1}(\dfrac{B_{E}}{B_{w}})

\theta=\tan^{-1}(\dfrac{20 \mu}{24.4 \mu})

\theta=39.3^{\circ}

Hence, The absolute value of the angular deviation is 39.3°.

5 0
3 years ago
I need help on 7 and 8 thanks
Sauron [17]
8. 107.1 MHz

7. 90.5 MHz
5 0
3 years ago
A 15.0-m uniform ladder weighing 500 N rests against a frictionless wall. The ladder makes a 60.08 angle with the horizontal. (a
grigory [225]

Answer:

a)  fr = 266.92 N,   fy = 1300 N,  b)    μ = 0.36

Explanation:

a) This is a balancing act.

Let's write the rotational equilibrium relations, where the turning point is the bottom of the ladder and the counterclockwise rotations are positive

             -w x - W x₂ + R y = 0         (1)

usemso trigonometry to find distances

            cos 60.08 = x / 7.5

            x = 7.5 cos 60.08

            x = 3.74 m

fireman

           cos 60.08 = x₂ / 4

           x2 = 4 cos 60

           x2 = 2 m

wall support

           sin 60.08 = y / 15

           y = 15 are 60.08

           y = 13 m

we substitute in equation 1

           R y = w x + W x2

            R = (w x + W x2) / y

            R = (500 3.74 +800 2) / 13

            R = 266.92 N

now let's write the expressions for the translational equilibrium

X axis

           R -fr = 0

           R = fr

           fr = 266.92 N

Y Axis  

           Fy - w-W = 0

           fy = 500 + 800

           fy = 1300 N

b) ask the friction coefficient

the firefighter's distance is

          cos 60.08 = x₃ / 9.00

          x₃ = 9 cos 60

          x₃ = 5.28 m

from equation 1

          R = (w x + W x₃) / y

          R = 500 3.74 + 800 5.28) / 13

          R = 468.769 N

we saw that

          fr = R = 468.769

The expression for the friction force is

          fr = μ N

in this case the normal is the ratio to pesos

        N = Fy

       N = 1300 N

        μ N = fr

        μ = fr / N

        μ = 468,769 / 1300

         μ = 0.36

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