9514 1404 393
Answer:
a. plane DEA
Step-by-step explanation:
A plane can be named by naming any 3 non-collinear points in the plane, or by using the plane's name as indicated in the drawing.
Here, points in the plane are A, D, E, F, with DEF all on the same line. So A plus any two points from the line will constitute a name for the plane. Also, this plane is identified with a script M that can be used to name the plane.
M is not an answer choice, but DEA is. So, the appropriate choice is ...
plane DEA
__
F is a point, not a plane name. C is not on the plane, so cannot be used to name it. 'k' is a line name, not a plane name.
A = 4,
we denote one side of the rectangle with
a
, and the other with
b
we can write, that:
a
⋅
b
=
16
so we can write, that
b
=
16
a
Now we can write perimeter
P
as a function of
a
P
=
2
⋅
(
a
+
16
a
)
We are looking for the smallest perimeter, so we have to calculate derivative:
P
(
a
)
=
2
a
+
32
a
P
'
(
a
)
=
2
+
(
−
32
a
2
)
P
'
(
a
)
=
2
−
32
a
2
=
2
a
2
−
32
a
2
The extreme values can only be found in points where
P
'
(
a
)
=
0
P
'
(
a
)
=
0
⇔
2
a
2
−
32
=
0
2
a
2
−
32
=
0
x
a
2
−
16
=
0
×
x
.
.
a
2
=
16
×
×
x
a
=
−
4
or
a
=
4
Since, length is a scalar quantity, therefore, it cannot be negative,
When
a
=
4
,
b
=
16
4
b
=
4
Answer:
23
Step-by-step explanation:
First subtract 7 and 4.
7-4=3
6-3=3
________
7+3+6+3+4
7+3=10
10+6=16
16+3=19
19+4=23
(Ignore the 3 inside the shape)
Answer: D
Step-by-step explanation: Using pemdas parentheses is always first so the answer is D.
Answer:
y = 126.43
Step-by-step explanation:
Essentially what you have is the Cosine(50)
Cos(50) = adjacent / hypotenuse
adjacent = 122
hypotenuse = ?? = y
Solve
Cos(50) = 122/y Multiply both sides by y
y*cos(50) = 122 Divide by cos(50)
y = 122 / cos(50) Find the value of cos(50)
y = 122 / 0.96497 Divide
y = 126.43
