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sergey [27]
2 years ago
9

Which of the following particles is similar to a He nucleus?

Physics
2 answers:
Pachacha [2.7K]2 years ago
6 0
I think it would be an Alpha Particle.
Marat540 [252]2 years ago
4 0
<h2>Answer:</h2>

Alpha

<em>I hope this helps you</em>

<em>:)</em>

You might be interested in
Which statement accurately describes the big bang theory? The universe began at an outer boundary and has been collapsing since
iren [92.7K]

Answer: The statements are missing hence I will give you a summary of what the big bang theory .

answer : The big bang theory explains how the energies of every speck of the universe came together at a point ( very dense point ) and eventually exploded creating the various galaxies we have today

Explanation:

The Big bang theory describes how the Universe and the various galaxies that exist began some billion of years ago, It describes how the energies of every speck of the universe came together at a point ( very dense point ) and eventually exploded creating the various galaxies we have today

5 0
3 years ago
If the velocity of an object is 9 m/s and its momentum is 72 kgm/s, what is its mass
MAVERICK [17]

An object with a velocity (v) of 9 m/s and a linear momentum (p) of 72 kg.m/s, has a mass (m) of 8 kg.

<h3>What is momentum?</h3>

In Newtonian mechanics, linear momentum, or simply momentum, is the product of the mass and velocity of an object.

It is a vector quantity, possessing a magnitude and a direction.

The mathematical expression for momentum is:

p = m . v

where,

  • p is the linear momentum of the object.
  • m is the mass of the object.
  • v is the velocity of the object.

An object has a velocity (v) of 9 m/s and its linear momentum (p) is 72 kg.m/s. We will use the definition of linear momentum to calculate the mass of the object.

p = m . v

m = p / v

m = (72 kg.m/s) / (9 m/s) = 8 kg

An object with a velocity (v) of 9 m/s and a linear momentum (p) of 72 kg.m/s, has a mass (m) of 8 kg.

Learn more about linear momentum here: brainly.com/question/7538238

#SPJ1

5 0
2 years ago
A horizontal beam of electrons initially moving at 4.0×10^7 m/s is deflected vertically by the vertical electric field between o
givi [52]

Answer:

1.77\times 10^{-7}\ C/m^2

0.000439077936334 m

Explanation:

q = Charge of electron = 1.6\times 10^{-19}\ C

E = Electric field = 2\times 10^{4}\ N/C

\epsilon_0 = Permittivity of free space = 8.85\times 10^{-12}\ F/m

d = Distance between plates = 2 cm (assumed)

m = Mass of electron = 9.11\times 10^{-31}\ kg

The beam consists of electrons which means it has negative charge this means the upper plates will be positive and the lower plate will be negative.

The direction is upper to lower lower plate.

\epsilon_0 = Permittivity of free space = 8.85\times 10^{-12}\ F/m

Electric flux is given by

\phi=\epsilon_0E\\\Rightarrow \phi=8.85\times 10^{-12}\times 2\times 10^{4}\\\Rightarrow \phi=1.77\times 10^{-7}\ C/m^2

The charge per unit area on the plates is 1.77\times 10^{-7}\ C/m^2

Deflection is given by

s=\dfrac{1}{2}\dfrac{qE}{m}(\dfrac{d}{v})^2\\\Rightarrow s=\dfrac{1}{2}\dfrac{1.6\times 10^{-19}\times 2\times 10^4}{9.11\times 10^{-31}}(\dfrac{0.02}{4\times 10^7})^2\\\Rightarrow s=0.000439077936334\ m

The deflection is 0.000439077936334 m

7 0
3 years ago
What is an analogy of two different roads or rivers to compare a series and parallel circuit?
faltersainse [42]

Answer:

In a series circuit, the same amount of current flows through all the components placed in it. On the other hand, in parallel circuits, the components are placed in parallel with each other due to which the circuit splits the current flow.

5 0
2 years ago
The first hill of a roller coaster is 42 meters high. The top of the second hill of the one
Marta_Voda [28]

Answer:

Part a)

Speed of the roller coaster is

v = 13.3 m/s

Part b)

Since it is moving with non zero speed at some height above the ground

So we will have

Kinetic energy + Potential energy Both

Explanation:

As we know that there is no friction on the path

So here we can use mechanical energy conservation law

so we will have

Part a)

U_i  + K_i = U_f + K_f

mgh + 0 = \frac{1}{2}mv^2 + mgH

34500(9.81)(42) = \frac{1}{2}(34500)v^2 + 34500(9.81)(33)

v = 13.3 m/s

Part b)

Since it is moving with non zero speed at some height above the ground

So we will have

Kinetic energy + Potential energy Both

7 0
4 years ago
Read 2 more answers
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