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VikaD [51]
3 years ago
11

When you view the pendulum’s swing, it shows that at the very top of the swing KE = 0. What does that tell you about the pendulu

m’s motion at that point?
Physics
2 answers:
kolezko [41]3 years ago
7 0

Answer: The kinetic energy of an object is given by:

Kinetic energy = 1/2 * mass * velocity²

If the kinetic energy of the pendulum at the top of its swing is 0, then this tells us that the velocity of the pendulum at that point is 0. All of the kinetic energy is converted to potential energy, and the pendulum starts moving in the opposite direction after this point in time.

Explanation:

nadezda [96]3 years ago
5 0

it tells you that it has a lot of force

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The boiling point of water at sea level is 100 °c. at higher altitudes, the boiling point of water will be
Scilla [17]
   <span> The boiling point of water at sea level is 100 °C. At higher altitudes, the boiling point of water will be.....
a) higher, because the altitude is greater.
b) lower, because temperatures are lower.
c) the same, because water always boils at 100 °C.
d) higher, because there are fewer water molecules in the air.
==> e) lower, because the atmospheric pressure is lower.
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Water boils at a lower temperature on top of a mountain because there is less air pressure on the molecules.
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I hope this is helpful. </span>
8 0
3 years ago
When exposed to a radioactive source which emits 1.2-MeV gamma-rays, a particular material is found to have a half-value thickne
iren2701 [21]

Answer:E

Explanation:

It is given that Energy of gamma ray is E=1.2 Mev

Shielding effect can be measured by measuring the fraction of gamma rays blocked by shield. If certain thickness will able to block half the radiation then to block 75% radiation we need to add same amount of thickness in order to block the remaining radiation.

i.e. \frac{E}{2} fraction is blocked by 10 cm thickness

then remaining radiation is \frac{E}{2}

another 10 cm thickness will block the remaining half radiation i.e. \frac{1}{2}\times \frac{E}{2}=\frac{E}{4}

so total 75 % radiation will be blocked

4 0
3 years ago
How long Tina, a ballerina, in the air when she leaps straight up with a speed of 1.8 m/s?
Tems11 [23]

The acceleration of gravity on or near the surface of the Earth is 9.8 m/s².
Anything acted on only by gravity loses 9.8 m/s of upward speed, or gains
9.8 m/s of downward speed, every second.

Leaping straight upward at 1.8 m/s, Tina keeps rising until she runs out of
upward speed.  That happens in (1.8/9.8) = 0.1837 second after the leap.

After that, Finkel's First Law of Motion takes over:
"What goes up must come down."

The dropping part of the leap is symmetrical with the first.  Please don't
make me go through proving it.  Tina hits the floor at the same speed of
1.8 m/s with which she left it, and it takes the same amount of time to drop
from the peak to the floor as it took to rise from the floor to the peak.

So her total time out of contact with the floor is

                     2 x (0.1837 sec)  =  0.367 second  (rounded)

3 0
3 years ago
A 10-kg object is pushed across a rough surface. It begins at rest and accelerates to a speed of 4 m/s in a distance of 5m. Whic
brilliants [131]

Answer:

Explanation:

Unbalanced Force according to newton's second law is the one which causes  the object to move or break its state of rest on application of force.

Here the object accelerate to a speed of 4 m/s and moves a distance of 5 m on application of force .

Thus we can say that the applied force is unbalanced in nature.

5 0
3 years ago
A basketball of mass 0.23kg is thrown horizontally against a rigid vertical wall with a velocity of 20m/s. It rebounds with a ve
Anna11 [10]

Answer:

8.1\:\mathrm{Ns}

Explanation:

The impulse-momentum theorem gives the impulse on an object to be equal to the change in momentum of that object. Since mass is maintained, the change in momentum of the basketball is:

\Delta p = m\Delta v, where m is the mass of the basketball and \Delta v is the change in velocity.

Since the basketball is changing direction, its total change in velocity is:

\Delta v = 20-(-15)=35\:\mathrm{m/s}.

Therefore, the basketball's change in momentum is:

\Delta p = m\Delta v = 0.23\cdot 35= 8.05=8.1\:\mathrm{kg\cdot m/s}.

Thus, the impulse on the basketball is \fbox{$8.1\:\mathrm{Ns}$} (two significant figures).

7 0
3 years ago
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