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Nikolay [14]
3 years ago
6

58.5g of sodium iodide are dissolved in 0.5dm3. what concentration would this be?

Chemistry
1 answer:
Bezzdna [24]3 years ago
7 0
percent by mass=(mass of solute/ mass of solution)*100 %

mass of solute=58.5 g

density (H₂O)=1 g/cm³*(1000 cm³/1dm³)=1000 g/dm³

mass of solvent (H₂O)=0.5 dm³ * (1000 g/dm³)=500 g
mass of solution=mass of solvent + mass of solut
mass of solution=58.5 g+500 g=558.5 g

% mass=(58.5 g/558.5 g) * 100%=10.47% of Na.

solution:  10.47% of Na.
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4 years ago
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4 years ago
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To determine the empirical formula of the hydrocarbon, we need to follow a series of steps.

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Step 2: Calculate the percent by mass of each element

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Step 4: Divide both numbers by the smallest one, i.e. 6.23

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The empirical formula of the hydrocarbon is CH₄.

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