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Soloha48 [4]
3 years ago
7

Calculate the density of an object with a mass of 3.8 g, that when placed in a 10.0 mL graduated cylinder with an initial volume

of 4.5 mL rises to a final volume of 8.6 mL. *
Chemistry
1 answer:
Arturiano [62]3 years ago
3 0

Answer : The density of an object is 0.93 g/mL

Explanation : Given,

Mass of an object = 3.8 g

Initial volume = 4.5 mL

Final volume = 8.6 mL

First we have to calculate the volume of an object.

Volume of an object = Final volume - Initial volume

Volume of an object = 8.6 mL - 4.5 mL

Volume of an object = 4.1 mL

Now we have to calculate the density of an object.

Formula used:

\text{Density}=\frac{\text{Mass of an object}}{\text{Volume of an object}}

Now putting all the given values in this formula, we get:

\text{Density}=\frac{3.8g}{4.1mL}

\text{Density}=0.93g/mL

Therefore, the density of an object is 0.93 g/mL

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38.25 grams of silicon is combined with 14.33 grams of nitrogen gas. How many grams of silicon nitride can be formed if nitrogen
zhuklara [117]
3Si + 2N2 --> Si3N4 (as given) 

n(Si) = m/MM = 38.25/28.085 = 1.3619 mol
n(N2) = 14.33/2*14.007 = 0.5115 mol

Therefore, N2 is limiting and Si is in excess 
The molar ratio of 2N2:Si3N4 is 2:1 
So, 0.0575 mol of silicon nitride is formed (dividing 0.5115 by 2) 

m of silicon nitride= n*mm = 0.0575*140.283 = 8.06627... g 
= 8.066g (4 significant figures) 

(hopefully it is right, but double check in case i did something wrong) :) 
6 0
3 years ago
What is the volume if 1.5 mol of gas has a pressure of 700 torr at 15°C?
Tasya [4]

Answer:

V = 38.48 L

Explanation:

Given that,

No. of moles = 1.5 mol

Pressure, P = 700 torr

Temperature, T = 15°C = 288 K

We need to find the volume of the gas. The ideal gas equation is given by :

PV=nRT\\\\V=\dfrac{nRT}{P}\\\\V=\dfrac{1.5\times 62.36\times 288}{700}\\\\V=38.48\ L, R = L.Torr.K⁻¹.mol⁻¹

So, the required volume is equal to 38.48 L.

7 0
3 years ago
What is the volume of 70.0 g of ether if the density of ether is 0.70 g/mL?
frosja888 [35]
M=70.0 g
p=0.70 g/mL

v=m/p

v=70.0/0.70=100.00 mL
8 0
3 years ago
A sample of iron absorbs 67.5 j of heat upon which the temperature of the sample increases from 21.5 °c to 28.5 °c. if the speci
asambeis [7]
Q = mcΔθ

67.5 = m x 0.45 x (28.5 - 21.5)

M = 67.5 / 3.15
= 21.4 g
3 0
3 years ago
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the following reaction gives a product with the molecular formula c4h8o2. draw the structure of the product.
grandymaker [24]

The following reaction gives a product with the molecular formula C₄H₈O₂. The diagram of the structure of the product can be seen in the image attached below.

The reaction between C₂H₂(ONa)₂ and C₂H₄Br results in the formation of the product C₄H₈O₂ and 2NaBr.

This reaction undergoes an SN₂ mechanism since there is no stable carbocation formed. In the reaction -O⁻Na⁺ attacks the ortho position in C₂H₄Br to form C₄H₈O₂.

In  SN₂ mechanism is a nucleophilic substitution reaction where one bond is formed while another one is broken simultaneously.

The mechanism for the reaction can be seen in the image attached below.

Learn more about nucleophilic substitution reaction here:

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7 0
2 years ago
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