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s344n2d4d5 [400]
2 years ago
8

The relationship between the endoplasmic reticulum and the Golgi complex is most similar to which of these examples? A a factory

that creates a product and the shipping department that delivers it to customers B a farmer who grows food and people who cook and eat that food in different ways C a bus that picks up passengers and the passengers who get out at different stops D a power plant that makes electricity and the town that uses it to light their houses
Chemistry
2 answers:
Schach [20]2 years ago
7 0

Answer: Answer is A

Explanation:

Len [333]2 years ago
4 0

Answer:

A

Explanation:

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Answer: Light Is Also a Particle!

Now that the dual nature of light as "both a particle and a wave" has been proved, its essential theory was further evolved from electromagnetics into quantum mechanics. Einstein believed light is a particle (photon) and the flow of photons is a wave.

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The more space and object has the larger it’s
olga55 [171]

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The larger the density is i think.

Explanation:

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Which of these is a common to all chemical changes
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C. A new substance is produced. All others are physical changes.
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2 years ago
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What is the limiting reactant when 20g CH4 react with 15g H20?
Art [367]

Answer:

H₂O.

Explanation:

  • It is clear from the balanced equation:

<em>CH₄ + 2H₂O → CO₂ + 4H₂.</em>

that 1.0  mole of CH₄ reacts with 2.0 moles of H₂O to produce 1.0 mole of CO₂ and 4.0 moles of H₂.

  • To determine the limiting reactant, we should calculate the no. of moles of (20 g) CH₄ and (15 g) H₂O using the relation:

<em>n = mass/molar mass</em>

<em></em>

no. of moles of CH₄ = mass/molar mass = (20 g)/(16 g/mol) = 1.25 mol.

no. of moles of H₂O = mass/molar mass = (15 g)/(18 g/mol) = 0.833 mol.

  • <em>from the balanced reaction, 1.0  mole of CH₄ reacts with 2.0 moles of H₂O.</em>

So, from the calculated no. of moles: 0.4167 mole of CH₄ reacts completely with 0.833 mole of H₂O and the remaining of CH₄ will be in excess.

<u><em>So, the limiting reactant is H₂O.</em></u>

4 0
2 years ago
How do you Calculate the molarity of 250 ml of solution in which 2.7 g of MgCl2 are dissolved
IRINA_888 [86]

Answer:

Molar mass of MgCl2 is 95 g/mol

Mg = 24 g/mol and Cl = 35.5 ×2 = 71 g/mol

moles = mass given/ molar mass

= 2.7/95 = 0.028 mol

volume = 250/1000 = 0.25 dm3 (ml is the same as dm3)

molarity of MgCl2 = moles/volume

= 0.028/0.25

= 0.112 mol/dm3

3 0
2 years ago
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