Complete Question
A dog weighs 2 pounds less than 3 times the weight of a cat. The dog weighs twenty two more pounds than the cat.
Write and solve an equation to find the weights of the cat and the dog.
Answer:
Weight of cat = x = 12 pounds
Weight of Dog = y = 34 pounds
Step-by-step explanation:
Let's represent:
Weight of cat = x
Weight of Dog = y
A dog weighs 2 pounds less than 3 times the weight of a cat.
y = 3x - 2........ Equation 1
The dog weighs twenty two more pounds than the cat
y = x + 22....... Equation 2
The equation is given as:
y = y
3x - 2 = x + 22
Collect like terms
3x - x = 22 + 2
2x = 24
x = 24/2
x = 12 pounds
Solving for y using any of the equations:
y = 3x - 2
y = 3 × 12 - 2
y = 36 - 2
y = 34 pounds
Therefore:
Weight of cat = x = 12 pounds
Weight of Dog = y = 34 pounds
Answer:
Step-by-step explanation:
P1 = (3.5,5) in the form (x1,y1)
P2 = (3.5,-12) in the form (x2,y2)
dist = sqrt[ (x2 - x1)^2 + (y2-y1)^2 ]
dist = sqrt[ (3.5-3.5)^2 + (-12-5)^2 ]
dist = sqrt [ 0 -17^2]
dist = 17
Answer:
a) - 7 dollars
b) 24.30 dollars
c) - 5 dollars
Step-by-step explanation:
b) 27 / 10%
Divide 27 by 10/100 by multiplying 27 by the reciprocal of 10/100.
27 x 100/10
Multiply 27 and 100 to get 2700.
2700/10
Divide 2700 by 10 to get 270.
270
Divide 270 by 100 to get 2.7
Subtract 27.00 - 2.7 = 24.30
24.30
Answer:
it is not possible because you only know 1 side. Unless you use cos sin
Step-by-step explanation:
Answer:
x = ± 4
Step-by-step explanation:
given 3x² = 48 ( divide both sides by 3 )
x² = 16 ( take the square root of both sides )
x = ± 
= ± 4
x ∈ {- 4, 4 }
