Let x =lenght, y = width, and z =height
<span>The volume of the box is equal to V = xyz </span>
<span>Subject to the surface area </span>
<span>S = 2xy + 2xz + 2yz = 64 </span>
<span>= 2(xy + xz + yz) </span>
<span>= 2[xy + x(64/xy) + y(64/xy)] </span>
<span>S(x,y)= 2(xy + 64/y + 64/x) </span>
<span>Then </span>
<span>Mx(x, y) = y = 64/x^2 </span>
<span>My(x, y) = x = 64/y^2 </span>
<span>y^2 = 64/x </span>
<span>(64/x^2)^2 = 64 </span>
<span>4096/x^4 = 64/x </span>
<span>x^3 = 4096/64 </span>
<span>x^3 = 64 </span>
<span>x = 4 </span>
<span>y = 64/x^2 </span>
<span>y = 4 </span>
<span>z= 64/yx </span>
<span>z= 64/16 </span>
<span>z = 4 </span>
<span>Therefor the dimensions are cube 4.</span>
For the answer to the question above, we will use this formula to solve this problem
<span>d = kv^2 </span>
<span>plugging in, </span>
<span>4.2 = k*10^2 </span>
<span>k = 0.042 </span>
<span>d = 0.042v^2 </span>
<span>the revoised equation will be </span>
<span>d = 0.9*0.042v^2 , i.e. </span>
<span>d = 0.0378v^2
I hope my answer helped you</span>
we are given
![\frac{\sqrt[3]{7}\sqrt{7}}{\sqrt[6]{7^5}}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%5Csqrt%5B3%5D%7B7%7D%5Csqrt%7B7%7D%7D%7B%5Csqrt%5B6%5D%7B7%5E5%7D%7D%20%20%20%20%20)
we can write it in terms of exponents
Firstly , we will simplify numerator
now, we can add exponents
we can cancel it
and we get
............Answer
Answer:
32 in, assuming 2 is your height, 208 in assuming 13 is your height
Step-by-step explanation:
Area = Base x Height
*You can always use this formula to find the area, but only for parallelograms
