Answer:
The value of the given expression is

Step by step Explanation:
Given that 
To find the value of 
Let us find the value of the expression :
( by using the formula
here A=2A)


(using
here A=2A)
(using
here A=2A)




( using
here A=2A )
(since tanA=a given )
Therefore 
I'm not sure what side is missing but you could use the proportions
A/B=X/Y or B/C=Y/Z or CA/=ZX. it also works if you reverse this for example B/A=Y/X
Answer:
6.5 seconds
Step-by-step explanation:
Keep in mind that when
, this is the same height for both when the model rocket takes off and lands, so when the rocket lands, time is positive. Thus:

So, the amount of seconds that the model rocket stayed above the ground since it left the platform is 6.5 seconds
Step-by-step explanation:
a) f(4) = 7-2(4)
= -1
b) f(h) = 7-2(h)
= 7-2h
c) f(4) + f(h) = -1 +(7-2h)
= 6-2h
h = 3
d) f(3+h) = 7-2(3+h)
= 7-6-2h
= -1-2h
2h= -1
h = -1/2
p/s = if the real answer is different with my answer, tell me also please. Im just a student that still learning.