(X-3)^2+5=14
Step 1: simplify both sides of the equation
X^2-6x+14=14
Step 2: subtract 14 from both sides
X^2-6x+14-14=14-14
X^2-6x=0
For this equation: a=1, b=-6,c=0
1x^2+-6x+0=0
Step 3: Use quadratic formula with a=1, b=-6, c=0
The answer is x=6 or x=0
-3(x+(3))^2-4 is the answer
Answer:
<u>600 meters</u>
Step-by-step explanation:
<u>Case 1 : Speed of 1 m/s</u>
- d = v * t
- d = 1 * t
- d = t [Equation 1]
<u>Case 2 : Speed of 1.5 m/s</u>
- d = v * t
- d = 1.5 * (t - 200)
- d = 1.5t - 300 [Equation 2]
As distance in both cases is the same, equate the values of d from both equations.
- t = 1.5t - 300
- 0.5t = 300
- t = 300 * 2
- <u>t = 600 s</u>
Now, put the value of t in <u>Equation 1</u> to find d.
Answer:
A. {x,y}={-2,-3}
// Solve equation [2] for the variable x
[2] x = 2y + 4
// Plug this in for variable x in equation [1]
[1] (2y+4) - y = 1
[1] y = -3
// Solve equation [1] for the variable y
[1] y = - 3
// By now we know this much :
x = 2y+4
y = -3
// Use the y value to solve for x
x = 2(-3)+4 = -2
B. [1] 3x=3y-6
[2] y=x+2
Equations Simplified or Rearranged :
[1] 3x - 3y = -6
[2] -x + y = 2
Solve by Substitution :
// Solve equation [2] for the variable y
[2] y = x + 2
// Plug this in for variable y in equation [1]
[1] 3x - 3•(x +2) = -6
[1] 0 = 0 => Infinitely many solutions
C.Step by Step Solution
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System of Linear Equations entered :
[1] 4x - y = 2
[2] 8x - 2y = 4
Solve by Substitution :
// Solve equation [1] for the variable y
[1] y = 4x - 2
// Plug this in for variable y in equation [2]
[2] 8x - 2•(4x-2) = 4
[2] 0 = 0 => Infinitely many solutions
