Question

The Petri dish shown has no lid. What is the surface area of the outside of the Petri dish? Round to the nearest tenth. A cylindrical-shaped Petri dish with a radius of 50 millimeters and a height of 15 millimeters.

Answer 1

Answer:

12566.4 mm²

Step-by-step explanation:

The Petri dish shown has no lid. What is the surface area of the outside of the Petri dish? Round to the nearest tenth. A cylindrical-shaped Petri dish with a radius of 50 millimeters and a height of 15 millimeters.

TSA = Total Surface Area

CSA = Curved Surface Area

TSA of open cylinder = CSA of cylinder + area of base or top

= 2πrh + πr²

= πr(2h + r)

From the above question:

r = 50mm

h = 15mm

Hence,

= π × 50 (2 × 15 + 50)

= π × 50 (30 + 50)

= π × 50(80)

= π × 4000

= 12566.370614mm²

Approximately = 12566.4 mm²

The Surface Area of the petri dish with no lid = 12566.4 mm²