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zaharov [31]
3 years ago
10

A map of a highway has A scale of 2 inches= 27 miles. The length of the highway on the map is 9 inches. There are 7 rest stops e

qually spaced on the highway, including one at each end. You’re making a new map with a scale of 1 inch= 30 miles. How far apart are the rest stops on the new map?
Mathematics
1 answer:
ser-zykov [4K]3 years ago
8 0

Answer:

From what i've researched, your answer might be "5 miles apart." or possilby "25.7 miles apart."

Step-by-step explanation

Im sorry if none of these answers are correct.

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Problems with Equations: Mastery Test
GaryK [48]

Step-by-step explanation:

The answer is 8

Because you have to put each value of x given in the equation 3x = 24

So when you put the value 8

3(8) = 24

24 = 24

6 0
4 years ago
What is 0.02% of 40 million pounds?
DanielleElmas [232]
0.02% of 40 million pounds is 8000 (pounds)

5 0
3 years ago
What decimal is longer than 8.5 cm
Leto [7]

Answer:

<h2>8.5555</h2>

Step-by-step explanation:

This number is not only larger, but also longer in digits than 8.5.

<h2>___________________________________________________</h2><h2><em>I AM ALWAYS HAPPY TO HELP :)</em></h2>
5 0
3 years ago
30 points!!<br> What is the sum of the first six terms of the series?<br> 48 - 12 + 3 - 0.75 +...
Lunna [17]

Answer:

The sum of the first six terms is 38.39

Step-by-step explanation:

This is a geometric sequence since the common difference between each term is -\frac{1}{4}

Thus, r=-\frac{1}{4}

To find the sum of first six terms, we need to find the fifth and sixth term of the sequence.

To find the fifth term:

The general form of geometric sequence is a_{n}=a_{1} \cdot r^{n-1}

To find the fifth term, substitute n=5 in a_{n}=a_{1} \cdot r^{n-1}

\begin{aligned}a_{5} &=(48) \cdot\left(-\frac{1}{4}\right)^{5-1} \\&=(48) \cdot\left(-\frac{1}{4}\right)^{4} \\&=(48)\left(\frac{1}{256}\right) \\a_{5} &=0.1875\end{aligned}

To find the sixth term, substitute n=6 in a_{n}=a_{1} \cdot r^{n-1}

\begin{aligned}a_{6} &=(48) \cdot\left(-\frac{1}{4}\right)^{6-1} \\&=(48) \cdot\left(-\frac{1}{4}\right)^{5} \\&=(48)\left(-\frac{1}{1024}\right) \\a_{5} &=-0.046875\end{aligned}

To find the sum of the first six terms:

The general formula to find Sn for |r| is S_{n}=\frac{a\left(1-r^{n}\right)}{1-r}

\begin{aligned}S_{6} &=\frac{48\left(1-\left(-\frac{1}{4}\right)^{6}\right)}{1-\left(-\frac{1}{4}\right)} \\&=\frac{48\left(1-\frac{1}{4096}\right)}{1+\frac{1}{4096}} \\&=\frac{48(0.95)}{5} \\&=\frac{48(0.9998)}{5} \\&=\frac{48(0.9998)}{5} \\&=\frac{47.9904}{5} \\&=38.39\end{aligned}

Thus, the sum of first six terms is 38.39

5 0
3 years ago
Please help........................
VashaNatasha [74]

Answer:

<h2>m∠ABD = 20°</h2>

Step-by-step explanation:

If m∠ABC = 40° and BD is the bisector of ∠ABC, then

(1) m∠ABD = m∠DBC

(2) m∠ABC = m∠ABD + m∠DBC

From (1) and (2) we have:

m∠ABC = 2m∠ABD

Therefore

2m∠ABD = 40°       <em>divide both sides by 2</em>

m∠ABD = 20°

3 0
3 years ago
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