.....to obey the law of conservation of mass.
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"1 x Ca = 1 x 40 = 40
1 x C = 1 x 12 = 12
3 x O = 3 x 16 = 48
40 + 12 + 48 = 100 (Mr of CaCO3)
moles = mass / Mr
mass = moles x Mr
mass = 1 mole x 100 = 100grams."</span><span>
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1978 to 2004 is <em>26 years</em>.
Every 5.23 years, half of our 200-gram sample decays.
It has reached its half life ~4.97 times.
We use this formula to find our new amount:
Every time it reaches its half life, it will be halved...the fractional exponent there is to pick up minute differences like in our 4.97.
Answer:
The estimated feed rate of logs is 14.3 logs/min.
Explanation:
The product of the process is 2000 tons/day of dry wood pulp, of 85 wt% of cellulose. That represents (2000*0.85)=1700 tons/day of cellulose.
That cellulose has to be feed by the wood chips, which had 47 wt% of cellulose in its composition. That means you need (1700/0.47)=3617 tons/day of wood chips to provide all that cellulose.
Th entering flow is wood chips with 45 wt% of water. This solution has an specific gravity of 0.640.
To know the specific gravity of the wood chips we have to write a volume balance. We also know that Mw=0.45*M and Mc=0.55*M.
The specific gravity of the wood chips is 0.494.
The average volume of a log is
The weight of one log is
To provide 3617 ton/day of wood chips, we need
The feed rate of logs is 14.3 logs/min.
There are about "36 ATP Molecules" are produced in cellular respiration
Hope this helps!