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zalisa [80]
3 years ago
7

You originally draw a design for an art contest on a 2 in. x 5 in. card. The second phase of the contest requires the drawing to

be transferred to an 8.5 in x 11 in. standard sheet of paper and utilize as much of the space on the paper as possible. You determine that the largest size one of the dimensions of your drawing can be is 10.5 in. What is the length of the other dimension if the two drawings are similar? Type your exact answer in the blank without the units, and round to the nearest tenths.
Mathematics
2 answers:
blagie [28]3 years ago
8 0

Answer:

Answer is 4.2 - I just took the quiz

Step-by-step explanation:

pentagon [3]3 years ago
4 0
<span><u><em>The correct answer is: </em></u>
4.2 inches.

<u><em>Explanation</em></u><span><u><em>: </em></u>
We use the size of the largest dimension of the reproduction to find the scale factor. The largest dimension of the original drawing was 5 inches.
The largest dimension of the reproduction is 11 inches.

<u>To find the scale factor, divide: </u>
</span></span>\frac{11}{5}<span><span>=2.1.

Since the scale factor is 2.1, to find the smallest dimension of the reproduction we <u>multiply the original by 2.1</u>:
 2*2.1=4.2 inches.</span></span>
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bogdanovich [222]
<h3>1. How many inches per minute does London's elevation change between 4 minutes and 8 minutes. </h3>

The question actually asks for the slope of the line that stands for the points (4,3) \ and \ (8,6) why? because the questions tells us that London's elevation changes between 4 minutes and 8 minutes here. Hence, to find the slope of this line we have to use the following formula:

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ \\ But: \\ \\ P(x_{1},y_{1})=P(4,3) \\ P(x_{2},y_{2})=P(8,6)

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ \\ But: \\ \\ P(x_{1},y_{1})=P(4,3) \\ P(x_{2},y_{2})=P(8,6) \\ \\ So: \\ \\ m=\frac{6-3}{8-4}=0.75in/min

<em>So London's elevation changes 0.75 inches per minute</em>

<em></em>

<h3>2. During which time period does London's elevation change the fastest?</h3>

The greater the absolute value of the slope of the line the faster London's elevation changes. Since this is a Piecewise function, we must analyze each period.

  • FIRST:

→ Between 0 minutes and 4 minutes the function is constant, so there is no any change here.

→ Between 10 minutes and 14 minutes the function is constant, so there is no any change here.

→ Between 18 minutes and 22 minutes the function is constant, so there is no any change here.

So the solution is not in these parts of the function.

  • SECOND:

→ Between 4 minutes and 10 minutes the function has a positive slope, so there is change here.

In the previous item we calculated the slope between 4 and 8 minutes that is the same slope between 4 and 8 minutes and equals 0.75.

→ Between 14 minutes and 18 minutes the function has a positive slope, so there is change here.

Let's take two points here, say, (16,5) \ and \ (18,3)

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ \\ But: \\ \\ P(x_{1},y_{1})=P(16,5) \\ P(x_{2},y_{2})=P(18,3) \\ \\ So: \\ \\ m=\frac{3-5}{18-16}=-1 in/min

As you can see, the absolute value here is 1 that is greater than 0.75.

<em>In conclusion, London's elevation changes the fastest between 14 and 18 minutes</em>

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Step-by-step explanation:

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