Answer:
a) 0.975 m
b) 13.25 m
Explanation:
given data:
pressure gage reading 130 kPa
a) mercury with density 13,600 kg/m^3
let distance between two fluid level is h,
then
we know that
13600*9.8*h=130*10^3
so h = 0.975 m
b.) water with density 1000 kg/m^3
let distance between two fluid level is h,
then
we know that
1000*9.8*h= 130*10^3
so h= 13.25 m
Answer:
v = 21.409 m/s
Explanation:
Given data:
Total weight of the platform and weight together, W = 900 N
Diameter of the water jet = 5 cm = 0.05 m
Now,
the force exerted by the water jet is balancing the platform
also,
Force exerted by the water jet = ρAv²
where,
ρ is the density of the water = 1000 kg/m³
A is the area of the outlet of the jet =
or
A = 0.00196 m²
v is the velocity of the jet
thus,
W = ρAv²
or
900 = 1000 × 0.00196 × v²
or
v = 21.409 m/s
Hence, the velocity of the jet is 21.409 m/s
Answer:
Kc = 1.0844
Maximum shear = 848.43 Mpa
Explanation:
Find attached of the calculations
Answer:
Option A
Explanation:
The size (volume) of the concrete pad is
cubic feet or 33.77 cubic yard
Cost of concrete per cubic yard dollars
Cost of concrete used in concrete pad is
dollar
The nearest answer to this question is option A
Answer:
See the attached file for the design.
Explanation:
Find attached for the explanation.