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1 year ago

Determine the force in each member of the truss. Stale if the members are in tension or compression. Prob.6-3

1 answer:

3 0

When a force is applied to a member and it is pointed at a joint, the member is in compression. When a force is directed away from a joint that the member is attached to, it is said to be in tension.

<h3>What is tension?</h3>

The pulling force transmitted axially by a string, rope, chain, or other similar object, or by each end of a rod, truss member, or other similar three-dimensional object, is referred to as tension in physics. Tension can also be described as the action-reaction pair of forces acting at each end of the aforementioned elements. Tension, the opposite of compression, is conceivable.

To measure tension as a transmitted force, an action-reaction pair of forces, or a restoring force, the International System of Units uses newtons (or pounds-force in Imperial units). At the point of attachment to the objects to which the string or rod is connected, the ends of a string or other object that transmits tension will exert forces in the direction of the string.

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3 years ago

The maximum stress that a bar will withstand before failing is called • Rapture Strength • Yield Strength • Tensile Strength • B

konstantin123 [22]

Answer: Rupture strength

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3 years ago

Using the Rayleigh criterion, calculate the minimum feature size that can be resolved in a system with a 0.18 NA lens when g-lin

Vladimir79 [104]

Answer:

# for a g line, R = 1.211 μm

# for an I-line, R = 1.013 μm

# for a g line, R = 0.726 μm

# for an I-line, R = 0.243 μm

# for a g line, R = 0.605 μm

# for an I-line, R = 0.608 μm

Explanation:

We know that;

Rayleigh Resolution R = 0.5 × λ/NA

for a g line, λ = 436 nm

for an I-line λ = 365 nm

Now when NA = 0.18

# for a g line, λ = 436 nm

R = 0.5 × 436/0.18 = 1.211 μm

# for an I-line λ = 365 nm

R = 0.5 × 365/0.18 = 1.013 μm

when NA = 0.30

# for a g line, λ = 436 nm

R = 0.5 × 436/0.30 = 0.726 μm

# for an I-line λ = 365 nm

R = 0.5 × 365/0.30 = 0.243 μm

when NA = 0.36

# for a g line, λ = 436 nm

R = 0.5 × 436/0.36 = 0.605 μm

# for an I-line λ = 365 nm

R = 0.5 × 365/0.30 = 0.608 μm

6 0

3 years ago

For an isotropic material, E and ν are often chosen as the two independent engineering constants. There are other elastic consta

pav-90 [236]

Answer:

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Explanation:

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3 years ago

We can model a certain battery as a voltage source in series with a resistance. The open-circuit voltage of the battery is 10 V

Angelina_Jolie [31]

Answer:

51.4 Ohms

Explanation:

By applying voltage division rule

$V_f=v_i\times \frac {R_l}{R_l+R_m}$ where v is voltage, subscripts i and f represnt initial and final, R is resistance, m is internal and l is external.Substituting 7V for final voltage, 10V for initial voltage and the external resistance as 120 Ohms then

$7=10*\frac {120}{120+R_m}\\7R_m+840=1200\\R_m={1200-840}{7}=51.428571\approx 51.4 Ohms$

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3 years ago