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romanna [79]
3 years ago
15

Brainiest and 35 points for the RIGHT ANSWER

Engineering
1 answer:
Mumz [18]3 years ago
5 0
A level it’s the only one that makes sense
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The specific volume of a system consisting of refrigerant-134a at 1.0 Mpa is 0.01 m /kg. The quality of the R-134a is: (a) 12.6%
Flura [38]

Answer:

option c is correct

47.2%

Explanation:

given data

consisting of refrigerant = 134 a

volume V = 0.01 m³/kg

pressure P = 1MPa = 1000 kPa

to find out

quality of the R 134a

solution

we will get here value of volume Vf and Vv from pressure table 60 kpa to 3 Mpa for 1 Mpa of R134 a

that is

Vf = 0.0008701 m³/kg

Vv = 0.0203 m³/kg

so we will apply here formula that is

quality = (V - Vf) / (Vv - Vf)    ............1

put here value

quality = (0.01 - 0.0008701 ) / ( 0.0203 - 0.0008701 )

quality = 0.4698

so quality is 47 %

SO OPTION C IS CORRECT

4 0
4 years ago
Write a CPP program that prompts the user to enter the number of lines and generates the following pattern of stars. If the nonn
WINSTONCH [101]

Answer:

Without Recursives

// Program is written using C++

// Comments are used for explanatory purpose

int main()

{

// Declare integer number, n

int n;

cout<<"Enter number of starts to print"

cin>>n;

// Iterate through to print * pattern

for(i=n; i>0;i--)

{

for(j=n; i>j-1;j--)

{

cout<<"*";

}

cout<"\n";

}

for(i=0; i< n; i++)

{

for(j=0;j<=i;j++)

{

cout<<"*";;

}

cout<"\n";

}

return 0;

}

Using Recursive

#include <iostream>

using namespace std;

void printStars(int lines);

int main()

{

// prompt the user to enter a number

int lines;

cin>> lines;

printStars(int lines);

return 0;

}

void printStars(int lines)

{

if (lines < 1)

return;

// to print the stars of a particular row

if (i <= lines)

{

cout << "* ";

// recursively print rest of the stars

// of the row

printPatternRecur(lines, i + 1);

}

else

{

// change line

cout << endl;

// print stars

printPatternRecur(lines-1, 1);

}

}

3 0
3 years ago
What are the functions of the peripheral nervous system
Margaret [11]

Answer:

The peripheral system allows the brain and spinal cord to receive and send information to other areas of the body, which allows us to react to stimuli in our environment.

The nerves that make up the peripheral nervous system are actually the axons or bundles of axons from nerve cells or neurons.

5 0
3 years ago
Read 2 more answers
At a given point in a supersonic wind tunnel, the pressure and temperature are 5×104 N/m2 and 200 K, respectively. The total pre
Ne4ueva [31]

Answer:

The Mach number is 2.866

Total temperature To = 528.524K

Explanation:

Pressure (P)= 5 * 10^4 N/m^2

Total pressure (Po) =  1.5 * 10^6 N/m^2

Temperature (T) = 200K

For air, r= 1.4

To find the Mach number we use:

Po/P = [1 + (r - 1/2) M^2] ^ r^/^r^-^1

1.5 * 10^6 / 5 * 10^4 =[ 1 + (1.4 -1 /2) (M^2) ] ^ 1^.^4^/^1^.^4^-^1

0.3 * 10^2 = (1 + 0.2M^2) ^3^.^5

(0.3 * 10^2)^(1/3.5) = 1 + 0.2M^2

2.6426 = 1 +0.2M^2

2.6426 - 1 = 0.2M^2

1.6426 = 0.2M^2

M^2 = 1.6426/0.2

M = sqrt(1.6426/0.2)

M = 2.866

To find Total Temperature :

To/T = (Po/P)^r^-^1^/^8) [tex][tex] To/200 = (1.5*10^6 / 5*10^4)^ 1^.^4^-^1^/^1^.^4)

To/200 = (0.3 * 10^2)^0^.^2^8^5^7

To =528.524K

4 0
3 years ago
A 15 Watt desk-type fluorescent lamp has an effective resistance of 200 ohms when operating (note: the 15 Watts is only associat
Aleks04 [339]

The question is incomplete! Complete question along with answers and explanation is provided below.

Question:

A 15 Watt desk-type fluorescent lamp has an effective resistance of 200 ohms when operating (note: the 15 Watts is only associated with the lamp). It is in series with a ballast that has a resistance of 80 ohms and an inductance of .9H. The lamp and ballast are operated at 120V, 60Hz.

a) Draw the circuit

b) Calculate the power drawn by the lamp

c) Calculate the apparent power

d) Calculate the power factor

e) Calculate the reactive power

f) Calculate the size of the capacitor necessary to provide unity power factor correction

Explanation:

a) draw the circuit

Refer to the attached image.

As you can see in the attached drawing, it is a series circuit containing  two resistors and one inductor.

In a series circuit, current remains same throughout the circuit

The circuit is powered by an AC voltage source having voltage of 120 V and frequency 60 Hz.

The current flowing in the circuit can be found by ohm's law

 I = V/Z

where V is the voltage and Z is the total impedance of the circuit

 Z = R + XL

where  XL is the inductive reactance

XL = j2 π f L

XL = j2*π*60*0.9

XL = j339.29Ω

Total resistance is

R =200 + 80 = 280 Ω

Total impedance is

Z = 280 + j339.29 Ω

b) Calculate the power drawn by the lamp

First calculate the current

I = V/Z

I = 120/(280 + j339.29)

I = 0.272<-50.46° A  (complex notation)

P = I²R

P = (0.272)²200

P ≈ 15 W

Power drawn by the circuit

P=V*I*cos(50.46°)

P=20.77 W

c) Calculate the apparent power

A = VI*

A = 120*0.272<50.46°

A = 32.64<50.46° VA

d) Calculate the power factor

PF = cos(50.46)

PF = 0.63

e) Calculate the reactive power

Q = VIsin(50.46)

Q = 120*0.272<-50.46*sin(50.46)

Q = 25.13<-50.46  VAR

f) Calculate the size of the capacitor necessary to provide unity power factor correction

The required reactive compensation power is

Qc = P (tan(old) - tan(new))

Qc = 20.77 (tan(50.46) - tan(0))

Qc = 25.16 VAR

C = Qc/2πfV²

C = 25.16/2*π*60*120²

C = 4.63 uF

Hence adding a capacitor of 4.63 uF parallel to the load will improve the PF from 0.63 to 1.

5 0
3 years ago
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