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solmaris [256]
4 years ago
10

Consider two identical 86-kg men who are eating identical meals and doing identical things except that one of them jogs for 30 m

in every day while the other watches TV. Determine the weight difference between the two in a month (30 days). An average 68-kg person consumes 540 Cal/h while jogging and 72 Cal/h while watching TV. The metabolizable energy content of 1 kg of fat is 33,100 kJ.

Engineering
1 answer:
Elena L [17]4 years ago
7 0

Answer:

The difference between the two in a month will be 1.04 Kg.

Explanation:

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Answer:

The following program is in C++.

#include <bits/stdc++.h>

using namespace std;

void lastChars(string s)

{

   int l=s.length();

   if(l!=0)

   {

       cout<<"The last character of the string is: "<<s[l-1];

   }

}

int main() {

   string s;//declaring a string..

   getline(cin,s);//taking input of the string..

   lastChars(s);//calling the function..

return 0;

}

Input:-

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Output:-

The last character of the string is: e

Explanation:

In the function lastChars() there is one argument that is a string.I have declared a integer variable l that stores the length of the string.If the length of the string is not 0.Then printing the last character of the string.In the main function I have called the function lastChars() with the string s that is prompted from the user.

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Answer:

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Answer:

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Explanation:

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Answer:

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