Answer:
The answer is "Option A".
Explanation:
Series:

Solving the above series:

So, the series is: 
Answer:
5.833
Explanation:
Coefficient of Perfomance (COP) is the ratio of refrigeration effect to power input.
where RE is refrigeration effect and P is power input
Here, the power input is given as 30 kW
We also know that 1 ton cooling is equivalent to 3.5 kW hence for 50 tons, RE=50*3.5=175 kW
Now the 
Answer:
A)
It should be Non- toxic
It should possess high Thermal conductivity
It should have the Required Thermal diffusivity
B)
- stoneware : This material has good thermal diffusivity and it is quite affordable and it is used in making pizza stones
- porcelain: mostly used for mugs and it is non-toxic
- Pyrex : posses good thermal conductivity used in oven
C) All the materials are suitable because they serve different purposes when making modern kitchen cookware
Explanation:
A) characteristics required of a ceramic material to be used as a kitchen cookware
- It should be Non- toxic
- It should possess high Thermal conductivity
- It should have the Required Thermal diffusivity
B) comparison of three ceramic materials as to their relative properties
- stoneware : This material has good thermal diffusivity and it is quite affordable and it is used in making pizza stones
- porcelain: mostly used for mugs and it is non-toxic
- Pyrex : posses good thermal conductivity used in ovens
C) material most suitable for the cookware.
All the materials are suitable because they serve different purposes when making modern kitchen cookware
The equations are based on the following assumptions
1) The bar is straight and of uniform section
2) The material of the bar is has uniform properties.
3) The only loading is the applied torque which is applied normal to the axis of the bar.
4) The bar is stressed within its elastic limit.
Nomenclature
T = torque (Nm)
l = length of bar (m)
J = Polar moment of inertia.(Circular Sections) ( m^4)
J' = Polar moment of inertia.(Non circluar sections) ( m^4 )
K = Factor replacing J for non-circular sections.( m^4)
r = radial distance of point from center of section (m)
ro = radius of section OD (m)
τ = shear stress (N/m^2)
G Modulus of rigidity (N/m^2)
θ = angle of twist (radians)