Answer:
i think its A. increasing research to find alternative natural resources for the future
Solution:
Given :
atomic radius, r = 0.1363nm = 0.1363×10⁻⁹m
atomic wieght, M = 95.96
Cell structure is BCC (Body Centred Cubic)
For BCC, we know that no. of atoms per unit cell, z = 2
and atomic radius, r =
so, a = 
m = mass of each atom in a unit cell
mass of an atom = 
,
where, 
is Avagadro Number = 6.02×10^{23}
volume of unit cell = a^{3}
density, ρ = 
density, ρ = 
ρ = 
ρ = 10.215gm/
Answer:
<em>d. </em><em>reducing </em><em>the </em><em>amount </em><em>of </em><em>recourses </em><em>spent </em><em>on </em><em>one </em><em>want </em><em>to </em><em>spend </em><em>more </em><em>on </em><em>another </em><em>want </em>
<em>brainliest</em><em>? </em><em>plz! </em>
Question
The mean weight of a breed of yearling cattle is 1187 pounds. Suppose that weights of all such animals can be described by the Normal model N(1187,78).
a) How many standard deviations from the mean would a steer weighing 1000 pounds be?
b) Which would be more unusual, a steer weighing 1000 pounds, or one weighing 1250 pounds?
Answer:
a. z = -2.40
A sleet weighing 1,000 pounds is 2.40 standard deviations below the mean.
b. z = 0.81
1000 is more unusual because its contained on the extreme end from the mean
Explanation:
a.
Let weight (in pounds) of the cattle be denoted by letter x:
z = (x - u)/ σ
Where u = mean and σ = standard deviation
u = 1187
σ = 78
x = 1000
Use z score formula to standardize the value of x:
z = (1000 - 1187)/78
z = -187/78
z = -2.397436
z = -2.40 ------_ Approximated
A sleet weighing 1,000 pounds is 2.40 standard deviations below the mean.
b.
x= 1250
z= (1250 - 1187)/78
z = 63/78
z = 0.807692
z = 0.81 --------- Approximated
1000 is more unusual because its contained on the extreme end from the mean
