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vitfil [10]
3 years ago
13

11) If the evaporating pressure was 76 psig for r-22and the compressor inlet temperature was 65f, what would be the total superh

eat entering the compressor
Engineering
1 answer:
Karolina [17]3 years ago
7 0
Saturated Pressure Temperature chart for R-22 shows 45 degF at 76 psig
65-45= 20 degF superheat



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It is known that the connecting rod AB exerts on the crank BCa 2.5-kN force directed down andto the left along the centerline of
monitta

Answer:

M_c = 61.6 Nm

Explanation:

Given:

F_a = 2.5 KN

Find:

Determine the moment of this force about C for the two casesshown.

Solution:

- Draw horizontal and vertical vectors at point A.

- Take moments about point C as follows:

                         M_c = F_a*( 42 / 150 ) *88

                         M_c = 2.5*( 42 / 150 ) *88

                         M_c = 61.6 Nm

- We see that the vertical component of force at point A passes through C.

Hence, its moment about C is zero.

6 0
3 years ago
According to the amortization table, Demarco and Tanya will pay a total of in interest over the life of their loan.
Ymorist [56]

Answer:

(Interest rate/number of payments)*$170000= interest for the first month.

Interest amounts for all the months of repayment plus $170000=Total loan cost

Explanation:

Interest is the amount you pay for taking a loan from a bank on top of the original amount borrowed.

Factors affecting how much interest is paid are; the principal amount, the loan terms, repayment schedule, the repayment amount and the rate of interest.

The interest paid=(rate of interest/number of payments to make)*principal amount borrowed.

You divide the interest with number of payments done in a year where monthly are divided by 12.Multiplying it by loan balance in the first month which is your principal amount gives the interest rate to pay for that month.

You new loan balance will be= Principal -(repayment-interest)

Do this for the period the loan should take.

Add all the interest amount to original borrowed amount to get total cost of the loan after the period of time.

8 0
3 years ago
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What are the relevance of report writing
nasty-shy [4]

Answer:Report writing consists of the history and facts of a project or of any kind of event. It is useful to record past history and an overall summary of decisions. Report writing helps to solve problems as a path. Writing a report will guide you in a way that will modernize details of the improvements and upcoming plans.

6 0
3 years ago
How does manufacturing affect the economy and society?
ratelena [41]

Explanation:

Because manufacturing has so many substantial links with so many other sectors throughout the economy, its output stimulates more economic activity across society than any other sector. That's a major reason manufacturers play such a critical role in growth.

6 0
3 years ago
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Steam at 4 MPa, 400°C enters a steady-flow, adiabatic turbine through a 20 cm-diameter-pipe with a velocity of 20 m/s. It leaves
Furkat [3]

Answer:

28,8 m/s

Explanation:

In a steady flow system we can say that m1=m2 which means that the mass flow in the entrance in the same in the outlet.  m is flow (kg/s)

we know that m=\frac{1}{v} A*V where V (m/s) is velocity, A (m^2) ia area and v is specific volume (m^3/kg)

Since m1=m2 we can say

\frac{1}{v_{1} } A_{1} *V_{1}=\frac{1}{v_{2}} A_{2} *V_{2}

clearing the equation

V_{2}= \frac{v_{2} }{v_{1}}*\frac{A_{1} }{A_{2}} *V_{1}

we can specific volume (m^3/kg) from thermodynamic tables

for the entrance is 400°C and 4 MPa is superheated steam and v is : 0,7343 m^3/kg

In the outlet we have saturated vapor with quality (x) of 80%. In this case we get the specific saturated volume for the liquid (vf) and the specific volume for the saturated  (vg) gas from the thermodynamic tables. we use the next equation to get  (v) for the condition of interest, in this case 80% quality.

v= vf +x*(vg - vf)

where:

x: quality

vf = liquid-saturated-specific-volume

vg =steam-saturated-specific-volume.

for this problem

x = 0,8

vf = 0,00102991

vg = 3,24015

so

we get = 2,593 m^3/kg

The area is the one for a circle

\pi *r^{2}

r1 = 0,1 m^2 for area 1

r2=0,5 m^2 for area 2

A1 = 0,0314 m^2

A2 = 0,7853 m^2

we know that  V1 is 20 m/s

replacing these values in the equation

V_{2}= \frac{v_{2} }{v_{1}}*\frac{A_{1} }{A_{2}} *V_{1}

we get V2 = 28,2 m/s.

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3 years ago
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