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2 years ago

13

11) If the evaporating pressure was 76 psig for r-22and the compressor inlet temperature was 65f, what would be the total superh

eat entering the compressor

1 answer:

Karolina [17]2 years ago

7 0

Saturated Pressure Temperature chart for R-22 shows 45 degF at 76 psig
65-45= 20 degF superheat

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_______ is a material property that pertains to local resistance to plastic deformation, such as scratching or denting. It is of

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Answer: hardness

Explanation:

Hardness is a measure of a material's ability to resist plastic deformation. In other words, it is a measure of how resistant material is to denting or scratching. Diamond, for example, is a very hard material. It is extremely difficult to dent or scratch a diamond. In contrast, it is very easy to scratch or dent most plastics.

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2 years ago

Suppose there are n chairs in a row. We want to compute the number of ways to put 2 students into seats so that they are not nex

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Complete Question

The complete question is shown on the first uploaded image

Answer:

a) $f_{(n)} = f_{(n-1)} + n-2$

b) $g_{(n)} = g_(n+1) + (n-2)$

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2 years ago

Write two scnr.nextInt statements to get input values into birthMonth and birthYear. Then write a statement to output the month,

aalyn [17]

Answer:

import java.util.Scanner;

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3 years ago

Yuri [45]

Answer:

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1 year ago

Read 2 more answers

Refrigerant 134a enters an air conditioner compressor at 4 bar, 20 C, and is compressed at steady state to 12 bar, 80 C. The vol

sleet_krkn [62]

Answer:

$Q=15.7Kw$

Explanation:

From the question we are told that:

Initial Pressure $P_1=4bar$

Initial Temperature $T_1=20 C$

Final Pressure $P_2=12 bar$

Final Temperature $T_2=80C$

Work Output $W= 60 kJ/kg$

Generally Specific Energy from table is

At initial state

$P_1=4bar \& T_1=20 C$

$E_1=262.96KJ/Kg$

With

Specific Volume $V'=0.05397m^3/kg$

At Final state

$P_2=12 bar \& P_2=80C$

$E_1=310.24KJ/Kg$

Generally the equation for The Process is mathematically given by

$m_1E_1+w=m_2E_2+Q$

Assuming Mass to be Equal

$m_1=m_1$

Where

$m=\frac{V}{V'}$

$m=frac{0.06666}{V'=0.05397m^3/kg}$

$m=1.24$

Therefore

$1.24*262.96+60)=1.24*310.24+Q$

$Q=15.7Kw$

4 0

3 years ago