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DENIUS [597]
4 years ago
14

2 examples of friction good and bad

Physics
1 answer:
liubo4ka [24]4 years ago
7 0
<span>✡ Answers:
Good
- </span><span>The reason that people and animals can walk. Because of friction we are able to walk one foot to the other.
- Prevents accidents, like being able to slam on a cars break and sliding endlessly.

Bad:
- When trying to go faster, friction can prevent that. In a car, or even trying to roller skate.
- It will damage the object that is sliding. Weather its skinning your knee of busting a tire. </span><span><span>✡</span>

</span>
✡Hope this helps<span>✡

</span>





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Según el diagrama anterior, ¿cómo se forman las rocas metamórficas?
torisob [31]

Answer:

A

Explanation:

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3 years ago
What is the voltage drop across the 10.0 ohm resistor?
DochEvi [55]

The voltage across all the resistors is the same i.e 120V

Each element of the parallel circuit has the same voltage applied to it. The total current flowing from the source is equal to the sum of the currents across each path. The electric potential difference (V) across each resistor in a parallel circuit is the same. Ohm's law states that I = V / R applies to the current in a resistor. The current will be lowest where the resistance is highest since the V is the same for each resistor. The currents passing through each resistor in a parallel combination have the same voltage across them because of their different resistance values and the laws of Ohms i., If two or more components are connected in parallel, they will be having same difference of potential (voltage) across their ends Parallel circuits are then used as current dividers.


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7 0
2 years ago
A driver enters a one-lane tunnel at 34.4 m/s. The driver then observes a slow-moving van 154 m ahead travelling (in the same di
navik [9.2K]

Answer:

Ans. B) 22 m/s (the closest to what I have which was 20.16 m/s)

Explanation:

Hi, well, first, we have to find the equations for both, the driver and the van. The first one is moving with constant acceleration (a=-2m/s^2) and the van has no acceletation. Let´s write down both formulas so we can solve this problem.

X(van)=5.65t+154

X(driver)=34.4t+\frac{(-2)t^{2} }{2}

or by rearanging the drivers equation.

X(driver)=34.4t+t^{2}

Now that we have this, let´s equal both equations so we can tell the moment in which both cars crashed.

X(van)=X(driver)

5.65t+154=34.4t-t^{2}

0=t^{2} -(34.4-5.65)t+1540=t^{2} -28.75t+154

To solve this equation we use the following formulas

t=\frac{-b +\sqrt{b^{2}-4ac } }{2a}

t=\frac{-b +\sqrt{b^{2}-4ac } }{2a}

Where a=1; b=-28.75; c=154

So we get:

t=\frac{28.75 +\sqrt{(-28.75)^{2}-4(1)(154) } }{2(1)}=21.63st=\frac{28.75 -\sqrt{(-28.75)^{2}-4(1)(154) } }{2(1)}=7.12s

At this point, both answers could seem possible, but let´s find the speed of the driver and see if one of them seems ilogic.

V(driver)=V_{0} +at}

V(driver)=34.4\frac{m}{s} -2\frac{m}{s^{2} } *(7.12s)=20.16\frac{m}{s}V(driver)=34.4\frac{m}{s} -2\frac{m}{s^{2} } *(21.63s)=-8.86\frac{m}{s}

This means that 21.63s will outcome into a negative speed, for that reason we will not use the value of 21.63s, we use 7.12s and if so, the speed of the driver when he/she hits the van is 20.16m/s, which is closer to answer  A).

Best of luck

8 0
3 years ago
Which statement correctly describes the differences between positive and negative acceleration?
Afina-wow [57]

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Hey

I tried to answer before and it dident let me.

8 0
3 years ago
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Acceleration = 1.3 m/s²

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Distance: ∫ 1.3x dx = 1.3x²/2 + c m

Distance run: 1.3*3²/2 = 5.85 m

<em>What</em><em> </em><em>bad</em><em> </em><em>thing</em><em> </em><em>happened</em><em>?</em>

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