This is called vaporization.
hope this helps :)
Answer:
A. We have that radius r = 4.00m intensity I = 8.00 W/m^
total power = power/ Area ( 4πr2)= 8.00 w/m^2( 4π ( 4.00 m)2=1607.68 W
b) I = total power/ 4πr2= 8.00 W/m2 ( 4.00 m/ 9.5 m)2= 1.418 W/m2
c) E = total power x time= 1607 . 68 W x 1s= 1607.68 J
Answer:
0.0319 m³
Explanation:
Use ideal gas law:
PV = nRT
where P is pressure, V is volume, n is amount of gas, R is the gas constant, and T is temperature.
Since P, n, and R are held constant:
n₁ R / P₁ = n₂ R₂ / P₂
Which means:
V₁ / T₁ = V₂ / T₂
Plugging in:
0.0279 m³ / 280 K = V / 320 K
V = 0.0319 m³
Answer:
final velocity will be44.72m/s
Explanation:
HEIGHT=h=100m
vi=0m/s
vf=?
g=10m/s²
by using third equation of motion for bodies under gravity
2gh=(vf)²-(vi)²
evaluating the formula
2(10m/s²)(100m)=vf²-(0m/s)²
2000m²/s²=vf²
√2000m²/s²=√vf²
44.72m/s=vf
