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2 years ago

6

Find a bank account balance if the account starts with $100, has an annual rate of 4%, and the money is left in the account for

12 years.

1 answer:

Mamont248 [21]2 years ago

5 0

100 x .4 = 40

40 x 12 = 480

The bank account would have $480 over 12 years. Hope this helps and please mark brainliest

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Write the equation of a circle with center (6,4) that passes through the coordinate (2,1). In your final answer, include all of

Elodia [21]

All points along the circle with be the distance of the radius from the center...so the radius can be found using the Pythagorean Theorem..

r^2=(4-1)^2+(6-2)^2

r^2=9+16

r^2=25

r=5

The equation of the circle can be expressed as:

r^2=(x-h)^2+(y-k)^2 where (h,k) correspond to the center of the circle, (2,1) in this case.

(x-2)^2+(y-1)^2=25

if you wanted it in a more standard form...

(y-1)^2=25-(x-2)^2

(y-1)^2=25-x^2+4x-4

(y-1)^2=-x^2+4x+21

y-1=(-x^2+4x+21)^(1/2)

y=1(+/-)(-x^2+4x+21)^(1/2)

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3 years ago

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What is the volume of this triangular pyramid?

valentina_108 [34]

Answer:

37.5 or 37 1/2

Step-by-step explanation:

You need to multiply length times width times height and then divide it by two.

5 0

2 years ago

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I WILL GIVE BRAINLIST

docker41 [41]

I’m pretty sure it’s true

8 0

2 years ago

∠EFG and ∠LMN are supplementary angles, m∠EFG=(3x+17)º, and m∠LMN=(12x−5)º.

Ira Lisetskai [31]

Answer:

EFG = 50.6, LMN = 129.4

Step-by-step explanation:

ok so s supplementary angles mean, their angles will always add upto 180. for example if one angle is 100° then the other will be 80°.

to find the angles first we need to solve for x.

we know EFG + LMN = 180 because its supplementary.

that's is (3x+17) + (12x-5) = 180.

we now solve for x;

15x+12 = 180

15x = 168, x= 168/15 = 11.2

now that we know x we can put this value in the corresponding equation of EFG and LMN to find the angles.

EFG = 3x11.2 + 17 = 50.6

LMN = 12x11.2 - 5 = 129.4

7 0

2 years ago

The market and Stock J have the following probability distributions:

denis-greek [22]

Answer:

1) $E(M) = 14*0.3 + 10*0.4 + 19*0.3 = 13.9 \%$

2) $E(J)= 22*0.3 + 4*0.4 + 12*0.3 = 11.8 \%$

3) $E(M^2) = 14^2*0.3 + 10^2*0.4 + 19^2*0.3 = 207.1$

And the variance would be given by:

$Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89$

And the deviation would be:

$Sd(M) = \sqrt{13.89}= 3.73$

4) $E(J^2) = 22^2*0.3 + 4^2*0.4 + 12^2*0.3 =194.8$

And the variance would be given by:

$Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56$

And the deviation would be:

$Sd(M) = \sqrt{55.56}= 7.45$

Step-by-step explanation:

For this case we have the following distributions given:

Probability M J

0.3 14% 22%

0.4 10% 4%

0.3 19% 12%

Part 1

The expected value is given by this formula:

$E(X)=\sum_{i=1}^n X_i P(X_i)$

And replacing we got:

$E(M) = 14*0.3 + 10*0.4 + 19*0.3 = 13.9 \%$

Part 2

$E(J)= 22*0.3 + 4*0.4 + 12*0.3 = 11.8 \%$

Part 3

We can calculate the second moment first with the following formula:

$E(M^2) = 14^2*0.3 + 10^2*0.4 + 19^2*0.3 = 207.1$

And the variance would be given by:

$Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89$

And the deviation would be:

$Sd(M) = \sqrt{13.89}= 3.73$

Part 4

We can calculate the second moment first with the following formula:

$E(J^2) = 22^2*0.3 + 4^2*0.4 + 12^2*0.3 =194.8$

And the variance would be given by:

$Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56$

And the deviation would be:

$Sd(M) = \sqrt{55.56}= 7.45$

8 0

3 years ago