Answer: A volume of 37.5 mL of 0.300 M NaF would be required to make a 0.0450 M solution of NaF when diluted to 250.0 mL with water.
Explanation:
Given: = 0.300 M, = ?
= 0.0450 M, = 250.0 mL
Formula used is as follows.
Substitute the values into above formula as follows.
Thus, we can conclude that a volume of 37.5 mL of 0.300 M NaF would be required to make a 0.0450 M solution of NaF when diluted to 250.0 mL with water.
Answer : The final temperature of the solution in the calorimeter is,
Explanation :
First we have to calculate the heat produced.
where,
= enthalpy change = 82.8 kJ/mol
q = heat released = ?
m = mass of = 5.10 g
Molar mass of = 110.98 g/mol
Now put all the given values in the above formula, we get:
Now we have to calculate the final temperature of solution in the calorimeter.
where,
q = heat produced = 3.80 kJ = 3800 J
m = mass of solution = 100 + 5.10 = 105.10 g
c = specific heat capacity of water =
= initial temperature =
= final temperature = ?
Now put all the given values in the above formula, we get:
Thus, the final temperature of the solution in the calorimeter is,
Answer:
Explanation:
Hello,
In this case, we use the Avogadro's number to compute the molecules of C2F4 whose molar mass is 100 g/mol contained in a 485-kg sample as shown below:
Best regards,
The largest number of molecules is the same as the largest number of moles of this molecules
to calculate the number of moles you have to divide the mass by the molar mass
molar masses:
CO2: 44,01 g/mol
CH4: 16,04 g/mol
CBr4: 331,63 g/mol
CHBr3: 252,73 g/mol
largest nº of mol= 100/(the smallest molar mass possible)
= 100/16,04
=6,23 moles
all other molecules would be smaller than 6,23 moles because the molar mass is so high.
The answer is B : 1<span>00 g of ch4</span>
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