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aalyn [17]
3 years ago
10

You are investigating an organic compound. you discover the following: it contains no hydrogen atoms. what property do you expec

t it to exhibit ?
a. has a foul odor
b. odorless
c. flammable
d. high boiling point
e. low boiling point
Chemistry
2 answers:
Juli2301 [7.4K]3 years ago
5 0

the answer is C because it has no water there will be nothing to boil and odor has nothing to do with hydrogen

I hope this helps! :)

-Ayden

Mashutka [201]3 years ago
4 0

Answer:

<u>Organic Compounds:</u>

The question itself is very wrong, as we can not attribute the name Organic compound just to any sort of compound which does not have the basic constituents inside its structure, as the absence of element hydrogen means that the compound which is under our observation is not O.C at all but it will be some other type of compound which will have a way different properties and structure.

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1 foot = 30.48 cm
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A 31.5 g wafer of pure gold initially at 69.4 ∘C is submerged into 63.4 g of water at 27.4 ∘C in an insulated container.
liubo4ka [24]

Answer: The final temperature of both substances at thermal equilibrium is 301.0 K

Explanation:

heat_{absorbed}=heat_{released}

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Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]         .................(1)

where,

q = heat absorbed or released

m_1 = mass of gold = 31.5 g

m_2 = mass of water = 63.4 g

T_{final} = final temperature = ?

T_1 = temperature of gold = 69.4^oC=342.4K

T_2 = temperature of water = 27.4^oC=300.4K

c_1 = specific heat of gold = 0.129J/g^0C

c_2 = specific heat of water= 4.184J/g^0C

Now put all the given values in equation (1), we get

-31.5\times 0.129\times (T_{final}-342.4)=[63.4\times 4.184\times (T_{final}-300.4)]

T_{final}=301.0K

The final temperature of both substances at thermal equilibrium is 301.0 K

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