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ad-work [718]
4 years ago
10

Approximately how tall is Baker Hill? Don't forget your unit

Chemistry
1 answer:
makvit [3.9K]4 years ago
5 0

Answer:

the elevation is 1,539

Explanation:

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You perform a distillation to separate a mixture of propylbenzene and cyclohexane, and you obtain 2.9949 grams of cyclohexane (d
Romashka-Z-Leto [24]

Answer:

66.67%

Explanation:

From the given information:

mass of cyclohexane = 2.9949 grams

density of cyclohexane = 0.779 g/mL

Recall that:

Density = mass/volume

∴

Volume = mass/density

So, the volume of cyclohexane = 2.9949 g/ 0.779 g/mL

= 3.8445 mL

Also,

mass of propylbenzene = 1.6575 grams

density of propylbenzene = 0.862 g/mL

Volume of propylbenzene =  1.6575 g/ 0.862 g/mL

= 1.9229 mL

The volume % composition of cyclohexane from the mixture is:

= (\dfrac{v_{cyclohexane}}{v_{cyclohexane}+v_{propylbenzene}})\times 100

= (\dfrac{3.8445}{3.8445+1.9229})\times 100

= (\dfrac{3.8445}{5.7674})\times 100

= 66.67%

6 0
3 years ago
Complete this worksheet. I DARE YOU!!! if you have the will power to
Colt1911 [192]

Answer:

Properties of metals, worksheet 6.1

Explanation:

Download pdf
4 0
3 years ago
Which equation represents positron decay?
jonny [76]

Answer: 4

Explanation:

4 is the only one that has to products as well as having the plus at the bottom

8 0
3 years ago
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joja [24]
I would suggest convection !!!
3 0
4 years ago
Read 2 more answers
32P has a half life of 14.0 days. If you order 60.0 grams of 32P and it took 46.7hrs from the time it was made to the time it wa
8090 [49]

Answer:

[A_t]=54.5\ g

Explanation:

Given that:

Half life = 14.0 days

t_{1/2}=\frac{\ln2}{k}

Where, k is rate constant

So,  

k=\frac{\ln2}{t_{1/2}}

k=\frac{\ln2}{14.0}\ days^{-1}

The rate constant, k = 0.04951 days⁻¹

Initial concentration [A₀] = 60.0 g

Time = 46.7 hrs

Considering, 1 hr = 0.041667 days

So, time = 1.9458 days

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

So,  

[A_t]=60.0\times e^{-0.04951\times 1.9458}\ g

[A_t]=54.5\ g

7 0
3 years ago
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