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2 years ago

1. Ill a parade, there are 36 clowns marching. The leader wants an

Mathematics

1 answer:

kykrilka [37]2 years ago

8 0

Answer:

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Use the points (0, 4) and (-2, 3) to find the slope of the line and give the equation of this line.

Sauron [17]

Answer:

Choice C: $m=\frac{1}{2}; y=\frac{1}{2} x+4$

Step-by-step explanation:

To find your slope do:

$\frac{y^2-y^1}{x^2-x^1}$

$\frac{3-4}{-2-0}=\frac{-1}{-2} =\frac{1}{2}$

that's how you get 1/2

4 is just the y-int.

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1 year ago

Write an equation of the graph:

katrin [286]

1. To translate to the left, add to x.
The equation is: y = |x + 2|

2. To translate down, add to y.
The equation is: y + 2 = |x| OR y = |x| - 2 (subtract 2 from each side)

Hope this helps!

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2 years ago

Does 12-(4x2)=(12-4)x(12-2)

Darina [25.2K]

No. Solve each of the problems and see if they match. Do PEMDAS order of operations

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2 years ago

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A polygon has an interior angle sum of 3060° how many sides must the polygon have?

AVprozaik [17]

Sum of interior angles=(n-2)180
3060=(n-2)180
3060/180=n-2
17=n-2
n=17+2
n=19..

5 0

3 years ago

Read 2 more answers

2 Here are two equations:

MatroZZZ [7]

a. (3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. No, it is not possible to have more than one (x,y) pair that is solution to both equations

Step-by-step explanation:

a. Decide whether each neither of the equations,

i (3,4)

ii. (4,2.5)

ill. (5,5)

iv. (3,2)

To decide whether each point is solution to equations or not we will put the point in the equations

Equations are:

Equation 1: 6x + 4y = 34

Equation 2: 5x – 2y = 15

i (3,4)

Putting in Equation 1:

$6(3) + 4(4) = 34\\18+16=34\\34=34\\$

Putting in Equation 2:

$5(3) - 2(4) = 15\\15-8 = 15\\7\neq 15$

ii. (4,2.5)

Putting in Equation 1:

$6(4) + 4(2.5) = 34\\24+10=34\\34=34\\$

Putting in Equation 2:

$5(4) - 2(2.5) = 15\\20-5 = 15\\15=15$

ill. (5,5)

$6(5) + 4(5) = 34\\30+20=34\\50\neq 34$

Putting in Equation 2:

$5(5) - 2(5) = 15\\25-10 = 15\\15=15$

iv. (3,2)

$6(3) + 4(2) = 34\\18+8=34\\26\neq 34$

Putting in Equation 2:

$5(3) - 2(2) = 15\\15-4 = 15\\11\neq 15$

Hence,

(3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. Is it possible to have more than one (x, y) pair that is a solution to both

equations?

The simultaneous linear equations' solution is the point on which the lines intersect. Two lines can intersect only on one point. So a linear system cannot have more than one point as a solution

So,

a. (3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. No, it is not possible to have more than one (x,y) pair that is solution to both equations

Keywords: Linear equations, Ordered pairs

Learn more about linear equations at:

#LearnwithBrainly

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2 years ago