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LUCKY_DIMON [66]
2 years ago
12

When are we going to abandon internal combustion engines?

Engineering
1 answer:
expeople1 [14]2 years ago
6 0

Answer:

2035

Explanation:

Most car and truck companies say that they will completely get rid of internal combustion engines by 2035.

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Why is an integrated circuit (IC) referred to as a special device?"<br> points more than 10 plz help
sladkih [1.3K]

Answer:

Because IC microcomputers are smaller and more versatile than previous control mechanisms, they allow the equipment to respond to a wider range of input and produce a wider range of output. They can also be reprogrammed without having to redesign the control circuitry

Explanation:

5 0
3 years ago
Which of the following materials will prevent the flow of electricity?
RUDIKE [14]
Electricity is not good at conducting through rubber materials so rubber tires would be the correct answer
3 0
3 years ago
Read 2 more answers
Determine the enthalpy, volume and density of 1.0 kg of steam at a pressure of 0.5 MN/m2 and with a dryness fraction of 0.96
Viktor [21]

Answer:

Enthalpy, hsteam = 2663.7 kJ/kg

Volume, Vsteam = 0.3598613 m^3 / kg

Density = 2.67 kg/ m^3

Explanation:

Mass of steam, m = 1 kg

Pressure of the steam, P = 0.5 MN/m^2

Dryness fraction, x = 0.96

At P = 0.5 MPa:

Tsat = 151.831°C

Vf = 0.00109255 m^3 / kg

Vg = 0.37481 m^3 / kg

hf = 640.09 kJ/kg

hg = 2748.1 kJ/kg

hfg = 2108 kJ/kg

The enthalpy can be given by the formula:

hsteam = hf + x * hfg

hsteam = 640.09 + ( 0.96 * 2108)

hsteam = 2663.7 kJ/kg

The volume of the steam can be given as:

Vsteam = Vf + x(Vg - Vf)

Vsteam = 0.00109255 + 0.96(0.37481 - 640.09)

Vsteam = 0.3598613 m^3 / kg

From the steam table, the density of the steam at a pressure of 0.5 MPa is 2.67 kg/ m^3

5 0
3 years ago
Please help me I don’t understand
Lapatulllka [165]

Answer:

A battery changes chemical energy to <u>electrical</u> energy

A drum changes mechanical energy to <u>sound</u> energy

Explanation:

A battery is a device that stores chemical energy and converts it to electrical energy.

Beating a drum represents a mechanical to sound energy  conversion.

4 0
3 years ago
Read 2 more answers
Bananas are to be cooled from 24°C to 13°C at a rate of 215 kg/h by a refrigeration system. The power input to the refrigerator
Leni [432]

Answer:

a) \dot Q_{L} = 132.046\,\frac{kJ}{min}, b) COP_{R} = 1.467

Explanation:

a) The heat rejected by the bananas is:

\dot Q_{L} = \dot m \cdot c\cdot (T_{f}-T_{o})

\dot Q_{L} = \left(215\,\frac{kg}{h}\right)\cdot \left(\frac{1\,h}{60\,min} \right)\cdot \left(3.35\,\frac{kJ}{kg\cdot ^{\textdegree}C}  \right)\cdot (24^{\textdegree}C-13\,^{\textdegree}C)

\dot Q_{L} = 132.046\,\frac{kJ}{min}

b) The coefficient of performance for the refrigeration system is:

COP_{R} = \frac{\dot Q_{L}}{\dot W}

COP_{R} = \frac{\left(132.046\,\frac{kJ}{min}\right)\cdot \left(\frac{1\,min}{60\,s} \right)}{1.5\,kW}

COP_{R} = 1.467

3 0
3 years ago
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