Seven colors are in the rainbow haha
Answer:
<em>181 °C</em>
<em></em>
Explanation:
Initial pressure
= 100 kPa
Initial temperature
= 30 °C = 30 + 273 K = 303 K
Final pressure
= 1200 kPa
Final temperature
= ?
n = 1.2
For a polytropic process, we use the relationship
(
/
) = (
/
)^γ
where γ = (n-1)/n
γ = (1.2-1)/1.2 = 0.1667
substituting into the equation, we have
(
/303) = (1200/100)^0.1667
/303 = 12^0.1667
/303 = 1.513
= 300 x 1.513 = 453.9 K
==> 453.9 - 273 = 180.9 ≅ <em>181 °C</em>
Answer:
quality ingredients and exceeding industry standards
Explanation:
Answer:
Given:
high temperature reservoir ![T_{H} =1000k](https://tex.z-dn.net/?f=T_%7BH%7D%20%3D1000k)
low temperature reservoir ![T_{L} =400k](https://tex.z-dn.net/?f=T_%7BL%7D%20%3D400k)
thermal efficiency ![n_{1}= n_{2}](https://tex.z-dn.net/?f=n_%7B1%7D%3D%20n_%7B2%7D)
The engines are said to operate on Carnot cycle which is totally reversible.
To find the intermediate temperature between the two engines, The thermal efficiency of the first heat engine can be defined as
![n_{1} =1-\frac{T}{T_{H} }](https://tex.z-dn.net/?f=n_%7B1%7D%20%3D1-%5Cfrac%7BT%7D%7BT_%7BH%7D%20%7D)
The thermal efficiency of second heat engine can be written as
![n_{2} =1-\frac{T_{L} }{T}](https://tex.z-dn.net/?f=n_%7B2%7D%20%3D1-%5Cfrac%7BT_%7BL%7D%20%7D%7BT%7D)
The temperature of intermediate reservoir can be defined as
![1-\frac{T}{T_{H} } =1-\frac{T_{L} }{T} \\T^2=T_{L} T_{H} \\T=\sqrt{T_{L} T_{H} }\\T=\sqrt{400*1000} =632k](https://tex.z-dn.net/?f=1-%5Cfrac%7BT%7D%7BT_%7BH%7D%20%7D%20%3D1-%5Cfrac%7BT_%7BL%7D%20%7D%7BT%7D%20%5C%5CT%5E2%3DT_%7BL%7D%20T_%7BH%7D%20%5C%5CT%3D%5Csqrt%7BT_%7BL%7D%20T_%7BH%7D%20%7D%5C%5CT%3D%5Csqrt%7B400%2A1000%7D%20%3D632k)
Answer:
the cycle is on the power just before the exhaust as both the valves are closed