Turn everything into decimals:
sqrt(3) is about 1.732
sqrt(5) is about 2.236
pi is about 3.14
2sqrt(3) is about 3.464
Now we can organize from least to greatest:
sqrt(3)<sqrt(5)<pi<2sqrt(3)
Hope this helped!
Answer: B
Step-by-step explanation:
For this case we have the following system of two equations with two unknowns:
We want to know if the point is the solution of the system:
We replace:
, meets the first equation.
does not comply with the second equation.
Therefore, it is not system solution.
Answer:
The point is not system solution
x^3 - 5x^2 + 6x - 30
| 1 - 5 6 - 30
|
|
5 | 5 0 30
----------------------------------------------
| 1 0 6 0 <------ the resiude is 0.
Resiude 0 means that the polynomial is divisible by x - 5, and that means the root is x = 5.
That is the only rooto because the quotient is x^2 + 6, which does not have real roots.
Answer: x = 5
Answer:
Step-by-step explanation:
To find the given asymptote of the given function, , first, compare the degrees of the lead term of the polynomial of the numerator and that of the denominator.
The numerator has a 2nd degree polynomial (x²).
The denominator has a 3rd degree polynomial (x³).
The polynomial of the numerator has a lower degree compared to the denominator, therefore, the horizontal asymptote is y = 0.