1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
prohojiy [21]
3 years ago
10

Observa la sucesion que llevan las figuras realiza las figuras que faltan ​

Mathematics
1 answer:
n200080 [17]3 years ago
5 0

Answer:

13, 16, 19, 22, 25, etc.

Step-by-step explanation:

You're pretty much just adding three for the chart. And for the diagram, you're adding two.

You might be interested in
Under average driving conditions, the life lengths of automobile tires of a certain brand are found to follow an exponential dis
wariber [46]

Answer:

a) P(X>30000)=1-( 1- e^{-\frac{30000}{30000}})=e^{-1}=0.368

b) P(X>30000|X>15000)=P(X>15000)=1-( 1- e^{-\frac{15000}{30000}})=e^{-0.5}=0.607

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

P(X=x)=\lambda e^{-\lambda x}, x>0

And 0 for other case. Let X the random variable that represent "life lengths of automobile tires of a certain brand" and we know that the distribution is given by:

X \sim Exp(\lambda=\frac{1}{30000})

The cumulative distribution function is given by:

F(X) = 1- e^{-\frac{x}{\mu}}

Part a

We want to find this probability:

P(X>30000) and for this case we can use the cumulative distribution function to find it like this:

P(X>30000)=1-( 1- e^{-\frac{30000}{30000}})=e^{-1}=0.368

Part b

For this case w want to find this probability

P(X>30000|X>15000)

We have an important property on the exponential distribution called "Memoryless" property and says this:

P(X>a+t| X>t)=P(X>a)  

On this case if we use this property we have this:P(X>30000|X>15000)=P(X>15000+15000|X>15000)=P(X>15000)

We can use the definition of the density function and find this probability:

P(X>15000)=1-( 1- e^{-\frac{15000}{30000}})=e^{-0.5}=0.607

7 0
3 years ago
Richard's weekly gross pay is $1,600. He pays 25% in federal income tax and 9% in state income
BlackZzzverrR [31]
His gross pay will be 9%
5 0
3 years ago
Read 2 more answers
R=4+7x-sx <br> I need help so any one can help with this
chubhunter [2.5K]
What do you need to solve for?

X=r-4/7-s

S=-r/x+4/x+7

R=-sx+7x+4
8 0
3 years ago
What number divided by 3 gives 12 as the result? A. -36 B. -4 С. 4 D. 36​
rodikova [14]
The answer is 36 all you do is divide the answer choices by 3 to get your answer
3 0
4 years ago
When m and I are cut by transversal n. if m&lt;3=67° , determine m&lt;6.​
marshall27 [118]

Answer:

  • 113°

Step-by-step explanation:

Angles 3 and 6 are consecutive interior angles

<u>As per definition, consecutive internal angles add to 180°</u>

  • m∠3 = 67° ⇒
  • m∠6 = 180° - 67° = 113°
3 0
3 years ago
Other questions:
  • What is 5mm as a radius plz help
    10·1 answer
  • Which repeating decimal is equal in value to the fraction below? 8/9
    13·2 answers
  • Can someone privately help me with a math problem
    6·1 answer
  • What is a qualitative graph?
    5·2 answers
  • Marcy needs 150 feet of fabric for her project. She uses 20% of it. How many feet of fabric did she use for her project so far?
    9·2 answers
  • Find the missing side in the right triangle, Round to the nearest tenth.<br><br> please help
    8·1 answer
  • Find the value for each trigonometric ratio. Reduce if<br> possible.<br> 5) cos À
    10·2 answers
  • Please help divide 10u^2− 4u/2u
    12·1 answer
  • Please help this is my last thing to do!!!
    6·1 answer
  • The perimeter of the triangle below is 42 units.<br> x + 5<br> Х<br> x+7<br> What is the value of x?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!