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adell [148]
3 years ago
10

Write the following series in sigma notation. 7 + 16 + 25 +34 +43 +52 + 61

Mathematics
1 answer:
Solnce55 [7]3 years ago
3 0

The series 7 + 16 + 25 +34 +43 +52 + 61 is an illusration of arithmetic series

The sigma notation of the series is: \sum\limits^7_{n=1} {9n - 2}

<h3>How to write the series in sigma notation?</h3>

The series is given as:

7 + 16 + 25 +34 +43 +52 + 61

The above series is an arithmetic series, with the following parameters

  • First term, a = 7
  • Common difference, d = 9
  • Number of terms, n = 7

Start by calculating the nth term using:

a(n) = a + (n - 1) * d

This gives

a(n) = 7 + (n - 1) * 9

Evaluate the product

a(n) = 7  - 9 + 9n

Evaluate the difference

a(n) = 9n - 2

So, the sigma notation is:

\sum\limits^7_{n=1} {9n - 2}

Read more about arithmetic series at:

brainly.com/question/6561461

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For a fair coin, the probability of tails is 1/ 2 or 0.5, so the probability of all tails in 10 tosess is (1/2)^10 = 1/1024 = 0.0009765625

Correct answer: D

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In an article in Marketing Science, Silk and Berndt investigate the output of advertising agencies. They describe ad agency outp
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Step-by-step explanation:

As per given , we have

Sample size : n= 392

Sample mean : \overline{x}=7.41\%

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Critical two-tailed z-value for 95% confidence = z_{\alpha/2}=1.96

Required confidence interval would be :

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4 years ago
Sam and Harry are family. Sam is currently is three times Harry's age. Sam's age is also 10 more than twice Henry's age. What ar
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Answer:

<em>Sam is 30 years old, and Harry is 10 years old.</em>

Step-by-step explanation:

Let us assume that the age of Sam is x and the age of Harry is y.

Sam is currently is three times Harry's age.

So, x=3y  ----------------------1

Sam's age is also 10 more than twice Harry's age.

so, x=2y+10  ---------------2

Subtracting 2 from 1, we get

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putting this in equation 1,

x=3(10)=30

Therefore, Sam is 30 years old, and Harry is 10 years old.

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Answer:

9 : 24

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Sum the parts of the ratio, 3 + 8 = 11 parts

Divide 33 by 11 to find the value of one part of the ratio

33 ÷ 11 = 3 ← value of 1 part of the ratio, thus

3 parts = 3 × 3 = 9

8 parts = 8 × 3 = 24

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