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alisha [4.7K]
1 year ago
7

I know the answers but my calculations won't provide them and i need to know what work to show

Mathematics
2 answers:
jeka941 year ago
7 0

a)\\\\(x+2)(x+5)\\\\=x(x+5) + 2(x+5)\\\\=x^2+5x+2x+10\\\\=x^2+7x+10\\\\\\b)\\\\(x+2)(x-3)\\\\=x(x-3)+2(x-3)\\\\=x^2-3x+2x-6\\\\=x^2-x-6

alexgriva [62]1 year ago
7 0
<h3>Step-by-step simplification:</h3>

≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡

1a) (x + 2)(x + 5)

⇒ (x × x) + (5 × x) + (2 × x) + (2 × 5)

⇒ (x²) + (5x) + (2x) + (10)

⇒ (x²) + (5 + 2)x + (10)

⇒ (x²) + (7)x + (10)

≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡

1b) (x + 2)(x - 3)

⇒ (x × x) + (-3 × x) + (2 × x) + (2 × -3)

⇒ (x²) + (-3x) + (2x) + (-6)

⇒ (x²) + (-3 + 2)x + (-6)

⇒ x² + (-1)x - 6 = x² - x - 6

≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡

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When Fiona rolled Cube #2, she got a number -2 as she got 2 while rolling Cube #1 and the sum of the value on the cubes was 0.

As we know Cube #1 has integers 1, 2, 3, 4, 5, 6 on its faces and Cube #2 has -1, -2, -3, -4, -5, -6 on its faces.

It is also given that Fiona got 2 when she rolled cube #1 and the value of the sum on both the cubes is 0.

So it is clear that on Cube #2, the number must be -2 as in that case only, the sum of the values will be 0.

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12. Find the measure of each interior angle of triangle QRT.
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Answer:

\angle QRT=125.6\°

\angle RTQ=6.4\°

\angle TQR=48\°

Step-by-step explanation:

It is important to remember that, by definition, the measure of an exterior angle of a triangle is equal to the sum of the measures of the two non-adjacent interior angles.

In this case we can idenfity that the angle 17x is an exterior angle of the triangle QRT. Then:

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Where:

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The sum of the interior angles of a triangle is 180°, therefore:

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Solving for \angle QRT, we get:

\angle QRT=180-48-6.4=125.6\°

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