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2 years ago

I know the answers but my calculations won't provide them and i need to know what work to show

Mathematics

2 answers:

jeka942 years ago

7 0

$a)\\\\(x+2)(x+5)\\\\=x(x+5) + 2(x+5)\\\\=x^2+5x+2x+10\\\\=x^2+7x+10\\\\\\b)\\\\(x+2)(x-3)\\\\=x(x-3)+2(x-3)\\\\=x^2-3x+2x-6\\\\=x^2-x-6$

alexgriva [62]2 years ago

7 0

<h3>Step-by-step simplification:</h3>

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1a) (x + 2)(x + 5)

⇒ (x × x) + (5 × x) + (2 × x) + (2 × 5)

⇒ (x²) + (5x) + (2x) + (10)

⇒ (x²) + (5 + 2)x + (10)

⇒ (x²) + (7)x + (10)

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1b) (x + 2)(x - 3)

⇒ (x × x) + (-3 × x) + (2 × x) + (2 × -3)

⇒ (x²) + (-3x) + (2x) + (-6)

⇒ (x²) + (-3 + 2)x + (-6)

⇒ x² + (-1)x - 6 = x² - x - 6

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PLEASE HELP

Tems11 [23]

QUESTION A

The given multiplication problem is

$\frac{39}{64} \times \frac{8}{13}$

Factor each term to obtain;

$\frac{13\times 3}{8\times8} \times \frac{8}{13}$

Cancel out the common factors to obtain;

$\frac{1\times 3}{8\times1} \times \frac{1}{1}$

Simplify to get;

$\frac{3}{8}$

QUESTION B

The given multiplication problem is

$\frac{2}{3}\times \frac{1}{5}\times \frac{4}{7}$

This the same as

$\frac{2\times 1\times 4}{3\times 5\times 7}$

This simplifies to;

$\frac{8}{105}$

QUESTION C

The given problem is

$\frac{3}{5}\times \frac{10}{12} \times \frac{1}{2}$

This is the same as

$\frac{3}{5}\times \frac{5}{6} \times \frac{1}{2}$

$=\frac{1}{1}\times \frac{1}{2} \times \frac{1}{2}$

This simplifies to

$=\frac{1}{4}$

QUESTION D.

The given expression is

$\frac{4}{9}\times 54$

Factor the 54 to obtain;

$\frac{4}{9}\times 9\times 6$

Cancel the common factors to get;

$\frac{4}{1}\times 1\times 6$

This simplifies to;

$=24$

QUESTION E

The given problem is

$20\times 3\frac{1}{5}$

Convert the mixed numbers to improper fraction to obtain;

$=20\times \frac{16}{5}$

$=4\times5 \times \frac{16}{5}$

Cancel the common factors to get;

$=4\times1 \times \frac{16}{1}$

$=64$

QUESTION F

The multiplication problem is

$11 \times 2 \frac{7}{11}$

Convert the mixed numbers to improper fractions to obtain;

$11 \times \frac{29}{11}$

Cancel out the common factors to get;

$=1 \times \frac{29}{1}$

Simplify;

$=29$

QUESTION G

The given problem is

$5\frac{1}{3}\times 5\frac{1}{8}$

Convert to improper fractions;

$=\frac{16}{3}\times \frac{41}{8}$

Cancel out the common factors to get;

$=\frac{2}{3}\times \frac{41}{1}$

$=\frac{82}{3}$

Convert back to mixed numbers

$=27\frac{1}{3}$

QUESTION H

The given expression is

$10\frac{2}{3} \times 1\frac{3}{8}$

Convert to improper fraction to get;

$\frac{32}{3} \times \frac{11}{8}$

Cancel common factors to get;

$=\frac{4}{3} \times \frac{11}{1}$

Simplify

$=\frac{44}{3}$

Convert back to mixed numbers;

$=14\frac{2}{3}$

7 0

3 years ago

Which one is correct?

jeka94

Answer:

The first one (A) is the answer I got!

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

El año pasado, la familia de Kate ahorró 2,573 monedas de 1¢. La familia de Zoe ahorró el triple de esa cantidad. ¿Cuántas moned

IRISSAK [1]

Answer:

brueh what im confused

Step-by-step explanation:

4 0

3 years ago

Hello, do you know how I do this?

Taya2010 [7]

Answer:

I think its this

14, 4, 18, 8, 22, 12, 26, 16...

Step-by-step explanation:

14-10

+14

-10

+14

-10

+14

-10

ect.

6 0

3 years ago

39. State the equation for the line described below.

devlian [24]

Answer:

Step-by-step explanation:

39). y = $-\frac{7}{8}$ x + 3

40). m = $\frac{y_{2} -y_{1} }{x_{2} -x_{1} }$

y - $y_{1}$ = m( x - $x_{1}$ )

(- 7, 5)

( - 12, 4)

m = ( 4 - 5 ) / ( - 12 + 7) = 1/5

y - 5 = (1/5)(x + 7) ⇒ y = $\frac{1}{5}$ x + 6.4

8 0

2 years ago