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2 years ago

What is the correct distribution of (2x-8)(3x-6) using the distributive property

Mathematics

2 answers:

Margaret [11]2 years ago

8 0

Answer:

6x² -36x +48

Step-by-step explanation:

The terms in one factor are each multiplied by the terms in the other factor. The resulting partial products are then combined. (This works the same as for numerical "long" multiplication.)

(2x -8)(3x -6) = 2x(3x -6) -8(3x -6)

= 6x² -12x -24x +48 . . . . . . . form partial products

= 6x² -36x +48 . . . . . . . collect terms

Shtirlitz [24]2 years ago

5 0

Answer:

6x² - 36x + 48

Step-by-step explanation:

(2x-8)*(3x-6) = 2x*3x + 2x* -6 + -8*3x + -8*-6

6x² - 12x - 24x + 48

6x² - 36x + 48 [Answer]

PLEASE RATE!! I hope this helps!!

if you have any questions comment below!!

(I have verified my answer using an online calculator)

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Complete the chart below to show the properties that hold true for the quadrilateral given in each row.

puteri [66]

Hey there!

Opposite sides are congruent:

all of them

opposite angles are congruent

rectangle and square

all sides are congruent

rhombus and square

diagonals congruent:

rectangle, rhombus, and square

diagonals are perpendicular

square and rhombus

Have a terrificly amazing day!

6 0

2 years ago

The USA won 15 Wimbledon championships. Sweden and Switzerland both won 7. Australia won 6, German won 4, and Spain won 2. Write

mihalych1998 [28]

Well you add the total of championships. 15+7+7+6+4+2=41
The ratio is 6:41
This means that Australia won 6 of the 41 championships.

5 0

3 years ago

ΔCAR has coordinates C (2, 4), A (1, 1), and R (3, 0). A translation maps point C to C' (3, 2). Find the coordinates of A' and R

shutvik [7]

Answer:

$A'= (2,-1)$ and $R'=(4,-2)$ under this translation.

Step-by-step explanation:

A translation in $R^{2}$ is a mapping T from $R^{2}$ to $R^{2}$ defined by $T(x,y) = (x + v_1,y+v_2)$ , where $v=(v_1,v_2)$ is a fixed vector in $R^{2}$ .

From the problem we know that $T(2,4)=(3,2)$ , so we need to find the values $v_1$ and $v_2$ such that $T(2,4) = (2 + v_1,4+v_2)=(3,2)$ , so $3=2 + v_1$ and $4+v_2=2$ , thus $v_1=1$ and $v_2=2$ .