Answer:
a) 66
b) 45
Step-by-step explanation:
We have 12 horses and after the first race 2 of them have to be eliminated
that condition is equal to consider that 10 horses will be available for the second race.
The number of possiblities we have for the first race is the combination of 12 horses in group of 10
C¹²₁₀ = 12!/ (2!)* (12-2)! = 12*11/2 = 66
For the second race
C¹⁰₈ = 10! / 8! * (10-8)! = 10*9/ 2 = 45
Answer:
Your answer would be 2
Step-by-step explanation:
15 - 6(x+1) =12
15- 6*x +6*1 = 12
15 - 6x + 6 = 12
15 - 6 + 6x = 12
9 + 6x = 12
9 - 9 + 6x = 12 - 9
6x = 3
x = 2
Answer:
51.32
Step-by-step explanation:
∠B = arcsin(b·sin(A)a)
= 0.67513 rad = 38.682° = 38°40'56"
∠C = 180° - A - B = 0.89566 rad = 51.318° = 51°19'4"
c = a·sin(C)sin(A) = 31.22499
Answer:
A.
Step-by-step explanation:
Answer:
Step-by-step explanation:
Ur answer should be B