$1.8:12.06=\dfrac{1.8}{12.06}=\dfrac{1.8\cdot100}{12.06\cdot100}=\dfrac{180}{1206}=\dfrac{180:6}{1206:6}=\dfrac{30}{201}=\dfrac{30:3}{201:3}=\dfrac{10}{67}$

3 0

3 years ago

For pigs, the length of pregnancies varies according to a normal distribution with a mean of 114 days and a standard deviation o

riadik2000 [5.3K]

Answer: The length of approximately 68% of all pig pregnancies will fall between 109 days and 119 days.

Step-by-step explanation:

According to the empirical rule , 68% of the population falls within one standard deviations from the mean.

Given : For pigs, the length of pregnancies varies according to a normal distribution with a mean of 114 days and a standard deviation of 5 days.

According to the Empirical Rule, the length of approximately 68% of all pig pregnancies will fall between $114-1(5)$ days and $114+1(5)$ days .

i.e. the length of approximately 68% of all pig pregnancies will fall between 109 days and 119 days.

7 0

3 years ago

Which equation could represent "the total cost of popcorn at the movie that sells for $2.50 each if p packages of popcorn are pu

andriy [413]

Let t=total cost
t=2.50p
hope this helps!

4 0

3 years ago

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