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Sedaia [141]
4 years ago
9

On earth, the solar constant is approximately I = 1367 W/m2 . This corresponds to the power per unit area that a detector at the

edge of the earth atmosphere would sense if perpendicular to the solar rays. This value can be obtained from the sun/earth geometry and by considering the sun as a blackbody at Tsun = 6000 K emitting radiation according to EEbb = σσTTssssss 4 where σσ = 5.67 × 10−8 W m−2K−4. Earth distance to sun = 150 000 000 km Mars to sun distance = 230 000 000 km With the information above, compute the solar constant in Mars. No need to do the actual calculation; instead, simply describe the step(s) you would take to solve the problem and list the relevant equation(s)
Physics
1 answer:
d1i1m1o1n [39]4 years ago
6 0

Answer:

Explanation:

for earth -sun system

E = σ T⁴ ,  E is radiation emitted by sun at temperature T

E = 4π R₁²  x solar constant on earth , R₁ is distance between earth and sun.

for marsh -sun system

E = σ T⁴ ,  E is radiation emitted by sun at temperature T

E = 4π R₂²  x solar constant on Mars , R₂ is distance between earth and sun.

from two equation ,

4π R₂²  x solar constant on Mars = 4π R₁²  x solar constant on earth

solar constant on Mars = (R₁ / R₂ )² x solar constant on earth

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