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maria [59]
3 years ago
15

A 3.0-cm-diameter tube is held upright and filled to the top with mercury. The mercury pressure at the bottom of the tube − the

pressure in excess of atmospheric pressure-is 48 kPa. How tall is the tube?
Physics
1 answer:
Lesechka [4]3 years ago
3 0

Answer:

Given a tube of diameter d, = 3cm = 0.03m

Pressure Balance

Mercury pressure at the tube bottom Pₓ = Pa + ρgh

where

Pa = Atmospheric pressure = 101kpa

ρ = Density of mercury = 13,546kg/m3

g = acceleration due to gravity

h = height of the tube?

Given

Bottom pressure in excess of the atmospheric pressure = 48kPa = Pₓ - Pa

Therefore, 48kPa = ρgh

h = 48(kN/m2)/ρg

h = 48,000kgms⁻²m⁻²/(13546kgm⁻³ x 9.81ms⁻²)

h = 0.36m

the tube is 36cm tall

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ra1l [238]

Answer:

The third particle should be at 0.0743 m from the origin on the negative x-axis.

Explanation:

Let's assume that the third charge is on the negative x-axis. So we have:

E_{1}+E_{3}-E_{2}=0

We know that the electric field is:

E=k\frac{q}{r^{2}}

Where:

  • k is the Coulomb constant
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  • r is the distance from the charge to the point

So, we have:

k\frac{q_{1}}{r_{1}^{2}}+k\frac{q_{3}}{r_{3}^{2}}-k\frac{q_{2}}{r_{2}^{2}}=0

Let's solve it for r(3).

\frac{3.01}{0.0429^{2}}+\frac{9.03}{r_{3}^{2}}-\frac{6.02}{0.0429^{2}}=0

r_{3}=0.0743\:  

Therefore, the third particle should be at 0.0743 m from the origin on the negative x-axis.

I hope it helps you!

 

3 0
3 years ago
How do Ohm's Law relate current, voltage difference, and resistance?
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The relationship between voltage, current, and resistance is described by Ohm's law. The equation, i = v/r, tells us that the current, i, flowing through a circuit is directly proportional to the voltage, v, and inversely proportional to the resistance, r.
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A blue-green photon (λ = 488 nm ) is absorbed by a free hydrogen atom, initially at rest. What is the recoil speed of the hydrog
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Answer:

The recoil speed is 2.207\times 10^{4} m/s

Solution:

Wavelength of a blue-green photon, \lambda_{BG} = 488 nm = 488\times 10^{- 9} m

Now, the energy associated with the blue-green photon:

E_{BG} = \frac{hc}{\lambda_{BG}}

where

h = Planck's constant

C = speed of light ion vacuum

E_{BG} = \frac{6.626\times 10^{- 34}\times 3\times 10^{8}}{488\times 10^{- 9}}

E_{BG} = 4.07\times 10^{- 19} J

Also, we know that the recoil speed can be calculated by the KInetic energy which is equal to the Energy of the blue-green photon:

KE_{H} =\frac{1}{2}m_{p}v_{H}

where

v_{H} = velocity of Hydrogen atom

m_{p} = 1.67\times 10^{- 27} kg = mass of H-atom

Now,

KE_{H} =\frac{1}{2}m_{p}(v_{H})^{2}

4.07\times 10^{- 19} =\frac{1}{2}\times 1.67\times 10^{- 27}\times (v_{H})^{2}

v_{H} = \sqrt(4.87\times 10^{8}) = 2.207\times 10^{4} m/s

7 0
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A group of students painted four cans, placed 500 grams of water in each can, and measured the temperature of the water as shown
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B.The water molecules in the black can had the largest increase in average kinetic energy.

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Here, black painted can absorbs more heat than the other color painted cans.

Black color absorbs all the heat and didn't reflect anything back, so it absorbs the most heat.

White color reflects all the heat, so heat absorbed by the white can is least.

When the black can absorbs heat then the water molecules in the can gets its maximum amount of kinetic energy so that the water molecules in the can collide with each other and also along with the walls of the can here, and so the average kinetic energy increases.

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A cause the sugar cubes are small enough to dissolve fast
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