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slavikrds [6]
3 years ago
14

Which of the following terms refers to areas of gas on the suns surface that are cooler than the gases around them?

Chemistry
2 answers:
solniwko [45]3 years ago
8 0
The answer is B sunspots
arlik [135]3 years ago
3 0
B: sunspots :) hope I helped
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Please help me out its due tmr :/
lesantik [10]

Answer:

using this for points, did you get the answer because I can try and help?

Explanation:

7 0
3 years ago
`What would be the proper way to write the formula for an ionic compound containing carbon and oxygen?
harina [27]
D because Carbon and Oxygen form covalent compounds. I wasn't the greatest at chem., but I'm pretty sure this is correct :D let me know if I gave you the right answer.
6 0
3 years ago
Which of the following is true?
Tomtit [17]

Answer:

a. A reaction in which the entropy of the system increases can be spontaneous only if it is endothermic.

Explanation:

The change in free energy (ΔG) that is, the <u>energy available to do work</u>, of a system for a constant-temperature process is:

ΔG = ΔH - TΔS

  • When ΔG < 0 the reaction is spontaneous in the forward direction.
  • When ΔG > 0 the reaction is nonspontaneous. The reaction is

spontaneous in the opposite direction.

  • When ΔG = 0 the system is at equilibrium.

If <u>both ΔH and ΔS are positive</u>, then ΔG will be negative only when the TΔS  term is greater in magnitude than ΔH. This condition is met when T is large.

3 0
3 years ago
What is the valency of CH3COO
WINSTONCH [101]

Answer:

thats too hard sorry

Explanation:

6 0
3 years ago
A very simple assumption for the specific heat of a crystalline solid is that each vibrational mode of the solid acts independen
MatroZZZ [7]

Answer:

4.7 kJ/kmol-K

Explanation:

Using the Debye model the specific heat capacity in kJ/kmol-K

c = 12π⁴Nk(T/θ)³/5

where N = avogadro's number = 6.02 × 10²³ mol⁻¹, k = 1.38 × 10⁻²³ JK⁻¹, T = room temperature = 298 K and θ = Debye temperature = 2219 K  

Substituting these values into c we have

c = 12π⁴Nk(T/θ)³/5  

= 12π⁴(6.02 × 10²³ mol⁻¹)(1.38 × 10⁻²³ JK⁻¹)(298 K/2219 K)³/5

= 9710.83(298 K/2219 K)³/5

= 1942.17(0.1343)³

= 4.704 J/mol-K

= 4.704 × 10⁻³ kJ/10⁻³ kmol-K

= 4.704 kJ/kmol-K

≅ 4.7 kJ/kmol-K

So, the specific heat of diamond in kJ/kmol-K is 4.7 kJ/kmol-K

7 0
3 years ago
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