Answer:
B) 0.32 %
Explanation:
Given that:
Concentration = 1.8 M
Considering the ICE table for the dissociation of acid as:-
The expression for dissociation constant of acid is:
![K_{a}=\frac {\left [ H^{+} \right ]\left [ {CH_3COO}^- \right ]}{[CH_3COOH]}](https://tex.z-dn.net/?f=K_%7Ba%7D%3D%5Cfrac%20%7B%5Cleft%20%5B%20H%5E%7B%2B%7D%20%5Cright%20%5D%5Cleft%20%5B%20%7BCH_3COO%7D%5E-%20%5Cright%20%5D%7D%7B%5BCH_3COOH%5D%7D)
Solving for x, we get:
<u>x = 0.00568 M</u>
Percentage ionization = 
<u>Option B is correct.</u>
To correct her measurement to standard temperature and pressure (STP), she must <span>make a volume correction based on a higher temperature of 273 K. The answer is letter B. This is in order to correct the temperature and pressure because correcting the volume will indicate that the temperature and pressure will result to the opposite result of the volume. This is because volume is indirectly proportional with pressure and temperature.</span>
Answer:
Statement B "Elements at the right side of the period are smaller in size" is not true.
Explanation:
Going through the rows of the elements in the period the size of the elements get continuously bigger.
Answer:
The Ph is 3
Explanation:
First of all, calculate the concentration of the acid.
The balanced equation of reaction is:
HCl + NaOH ===> NaCl + H2O
Using titration equation of formula
CAVA/CBVB = NA/NB
Where NA is the number of mole of acid = 1 (from the balanced equation of reaction)
NB is the number of mole of base = 1 (from the balanced equation of reaction)
CA is the concentration of acid = ?
CB is the concentration of base = 0.1M
VA is the volume of acid = 100 mL
VB is the volume of base = 1mL
Substituting
CA×100/0.1×1 = 1/1
Therefore CA =0.1×1×1/100×1
CA = 0.001 M (this is the hydrogen ion concentration)
Ph of the acid is calculated using
Ph = -log [H+]
= -log 0.001
= 3
Answer:
Make an observation.
Ask a question.
Form a hypothesis, or testable explanation.
Make a prediction based on the hypothesis.
Test the prediction.
Iterate: use the results to make new hypotheses or predictions.
