The balanced equation for the reaction is as follows
C₆H₁₂O₆ + 6O₃ --> 6CO₂ + 6H₂O
stoichiometry of glucose to CO₂ is 1:6
when 1 mol of glucose reacts - 6 mol of CO₂ are formed
therefore when 5.87 mol of glucose reacts - 6 x 5.87 mol = 35.22 mol
therefore 35.2 mol of CO₂ is formed
Hey there!
Sucrose is C₁₂H₂₂O₁₁.
Find molar mass of sucrose:
C: 12 x 12.01 = 144.12
H: 22 x 1.008 = 22.176
O: 16 x 11 = 176
--------------------------------
342.296 grams
That is the mass of one mole of sucrose.
We have 0.0287.
342.296 x 0.0287 = 9.82
The mass of 0.0287 moles of sucrose is 9.82 grams.
Hope this helps!
Explanation: Oxygen plays a very vital role in the life of aquatic animals. The dissolved oxygen in the water helps them to breathe under water.
Optimum level of oxygen for deep living animals like oysters, bottom feeders, crabs is around (1-6 mg/L), while the animals living on the upper side like fishes require a higher amount of around (4-6 mg/L).
If the oxygen concentration in the pond is not optimum, there will no aquatic life and hence, the ecosystem will be affected.
Hence, oxygen concentration affects the fishes that live in the pond to a higher extent.
