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Airida [17]
3 years ago
14

Alkenes can be converted to alcohols by reaction with mercuric acetate to form a ?-hydroxyalkylmercury(II) acetate compound, a r

eaction called oxymercuration. Subsequent reduction with NaBH4 reduces the C?Hg bond to a C?H bond, forming the alkyl alcohol, a reaction called demercuration. Draw the structures of the Hg-containing compound(s) and the final alcohol product(s) formed in the following reaction sequence, omitting, by products. If applicable, draw hydrogen at a chirality center and indicate stereochemistry via wedge-and-dash bonds.
Neutral produst (s) of oxymercuration. Include stereoisomers, if any

image from custom entry tool HG(OOCCH3)2

----------------->

H2O,THF

Chemistry
2 answers:
Pie3 years ago
8 0

Answer:

Alcohol will be end product in any case.

Explanation:

Alkenes are the class of organic compounds which are termed as unsaturated organic compounds. These compounds contain a single or multiple double bond depending upon the carbon chain length. The simplest alkene among many others is called Ethene with the molecular formula C2H4. Its molecular structure is H2C=CH2. The double bond present in any alkene serve as a nucleophilic component, meaning it will attack any element with partial positive to positive charge.

The process of introducing mercuric acetate to any alkene is termed as oxymercuration. This is a three step process. Please see the reference image.

As you can see there,

in first step, the double bond of an alkene attacks the mercury element which carries the positive, thereby dispositioning the acetate bond, and forming a cyclic mercury complex.

In second step, water acts as a nucleophile and attack on electrophilic (electron loving) carbon, which moves the bond towards mercury retaining mercury stability. In this step, oxygen of water molecule carries positive charge because of donating lone pair of electrons to the alkene carbon.

In third step, the acetate ion which left the mercury in first step, being a nucleophile attack the hydrogen of water molecule, donating the bonded pair to oxygen and restoring neutral charge over oxygen. It forms acetic acid which reconverts to mercuric acetate by subsequent reaction and therefore restores the catalyst.

If the first step, the oxymercurated compound is treated with Sodium Borohydride (NaBH4), the demercuration occurs leaving hydrogen at the same place where mercury was previously attached. It is termed as Oxymercuration-Reduction Reaction.It is a popular laboratory technique to achieve alkene hydration with Markovnikov selectivity while avoiding carbocation intermediates and thus the rearrangement which can lead to complex product mixtures.

Goshia [24]3 years ago
3 0

Answer:

The simplified mechanism and products are on the picture.

Explanation:

If we have the symmetrical alkene the addition of mercury and OH group is not regioselective but when we have more donors for one of Carbons in alkene then the OH group will go there.

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Answer:

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4 0
3 years ago
What is the temperature of 4.5 moles of a gas that occupies 50. mL at 1.35 atm?
devlian [24]

Answer:

T = 0.182 Kelvin

Explanation:

As we know that

PV = nRT\\

Where P is the pressure in atmospheric pressure

T is the temperature in Kelvin  

R is the gas constant  

V is the volume in liters

R = 0.08206

Substituting the given values in above equation, we get -

1.35 * \frac{50}{1000}= 4.5 * 0.08206* T\\

On rearranging, we get

T = \frac{1.35*50}{1000*0.08206*4.5} \\

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7 0
3 years ago
If i have 8 L of 0.25 M solution, how many miles of MgCl2 are present
qaws [65]

Answer:

2 moles

Explanation:

The following were obtained from the question:

Molarity = 0.25 M

Volume = 8L

Mole =?

Molarity is simply defined as the mole of solute per unit litre of solution. It is represented mathematically as:

Molarity = mole of solute/Volume of solution.

With the above equation, we can easily find the number of mole of MgCl2 present in 8 L of 0.25 M MgCl2 solution as follow:

Molarity = mole of solute/Volume of solution.

0.25 = mole of MgCl2 /8

Cross multiply to express in linear form

Mole of MgCl2 = 0.25 x 8

Mole of MgCl2 = 2 moles

Therefore, 2 moles of MgCl2 are present in 8 L of 0.25 M MgCl2 solution

4 0
3 years ago
Why do you elements in the same group have similar properties
lozanna [386]

Answer:

They have similar properties, because they share similar amounts of electrons in their outer shell, valence electrons! This means they will only be able to interact with other elements with those electrons so they often show similar properties.

Explanation:

7 0
3 years ago
Im to lazy to do this.
san4es73 [151]
D is correct answer
6 0
3 years ago
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