All categories

3 years ago

According to the enthalpy diagram below, which of the following statements is true?

Chemistry

2 answers:

mezya [45]3 years ago

8 0

Answer:

C. Arrow C indicated that the third intermidiate reaction is exothermic

Explanation:

stich3 [128]3 years ago

7 0

Answer:it will be c on edg 2021

Explanation:

You might be interested in

Mohr's salt is a pale green crystalline solid which is soluble in water. It is a 'double sulfate' which contains two cations, on

Veronika [31]

The gas is NH₃.
H₂ doesn't dissolve readily in water, SO₂ gives an acidic solution in water.

The solid residue is Fe(OH)₂.
FeSO₄ and Na₂SO₄ are soluble in water.

The answer is C.

3 0

3 years ago

100 points !!!! Write your answer beside each number. You should have 13 items labeled in all.

Arte-miy333 [17]

Answer:

Explanation:

1) Valence electrons

2) Electrons

3) 2 electrons on K-shell

4) 8 electrons on L-Shell

5) 18 electrons on M-shell

6) nucleus

7) Proton

8) neutron

9) principal energy level

10) atomic number

11) symbol of the atom

12) name of the atom

13) atomic mass

5 0

4 years ago

Stolb23 [73]

Answer:

Um english please I don’t know Jewish

Explanation:

6 0

3 years ago

Choose the solvent below that would show the greatest boiling point elevation when used to make a 0.10 m nonelectrolyte solution

postnew [5]

Answer is: 1) ccl4, kb = 29.9°c/m, carbon tetrachloride has the greatest boiling point elevation.

The boiling point elevation is directly proportional to the molality of the solution according to the equation: ΔTb = Kb · b.

<span> ΔTb - the boiling point elevation.
Kb - the ebullioscopic constant.
b - molality of the solution.
So the highest boiling poing elevation will be for solution with highest ebullioscopic constant because molality is the same.</span>

5 0

3 years ago

Read 2 more answers

Indicate what happens to the concentration of Pb2+ in each half cell

Taya2010 [7]

Answer:

Your questions requires diagrams of the cell to get which one is on the left or right. However, see the attached file below

The correct answer is (d) the left half-cell will decrease in concentration; and the right half-cell will increase in concentration.

Explanation:

The concentration of the Pb2+ increases in the oxidation half cell while the concentration of the Pb2+ decreases in the reduction half cell during the reaction.

In the Left Beaker (Left half cell), their is less concentration

Pb(s) ---> Pb2+(aq) + 2 e- Concentration of Pb2+(aq) increase ; Electrons going out from this side

In the Right Beaker (right half cell), their is more concentration

Pb2+(aq) + 2 e- ---> Pb(s) Concentration of Pb2+(aq) decrease ; Electrons coming in to this side

Electrons will flow from Left to Right direction.

3 0

3 years ago