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erik [133]
2 years ago
12

Polygon HJKL has vertices H(-3, 4), J(2, 6), K(2, 1), and L(-3, -1). What are the slopes of sides HJ, JK, KL, and LH and how wou

ld you classify HJKL?
Mathematics
1 answer:
aleksklad [387]2 years ago
4 0
<span> the slopes of sides HJ, JK, KL, and LH and how would you classify HJKL?</span>
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Which equation and solution represents each situation? Solutions may be rounded to the nearest tenth. What number is 74% of 58?
Zolol [24]

Given:

A number is 74% of 58.

To find:

The number.

Solution:

Let the unknown number be n.

The number n is 74% of 58.

n=\dfrac{74}{100}{58}

n=0.74\times 58

n=42.92

The required equation is n=0.74\times 58 and the solution (unknown number) is n=42.92.

Therefore, the correct option is B.

8 0
3 years ago
At a university, 60​% of the students who apply. Of the students the university​ accepts, 25% actually enroll If 2000 students​
sweet-ann [11.9K]

Answer:

300 students are enrolled.

Step-by-step explanation:

As the university accepts 60% of the students who apply.

As 2000 students apply, it means that:

2000 × 60% ⇒ 2000 × 0.6 = 1200 students are accepted

Out of these 1200, 25% enrolled

1200 × 25% ⇒ 1200 × 0.25 = 300 students are enrolled

Therefore, 300 students are enrolled.

5 0
3 years ago
Question 6
ad-work [718]

Answer:

The input for the method is a continuous function f, an interval [a, b], and the function values f(a) and f(b). The function values are of opposite sign (there is at least one zero crossing within the interval). Each iteration performs these steps: Calculate c, the midpoint of the interval, c = a + b2.

Step-by-step explanation:

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7 0
2 years ago
Select the favorable Outcomes for rolling double sixes
ira [324]
We want double sixes. This means that we want both the first roll and the second roll to be 6.

The given point is given as (r1 , r2) where:
r1 is output from first roll
r2 is output from second roll

Since we want both outputs to be 6, therefore, the answer would be: (6,6)
4 0
3 years ago
Suppose that the functions g and h are defined for all real numbers r as follows. gx) -4x +5 h (x) = 6x write the expressions fo
aleksandr82 [10.1K]

Answer: Our required values would be -10x+5, 2x+5 and -25.

Step-by-step explanation:

Since we have given that

g(x) = -4x+5

and

h(x) = 6x

We need to find  (g-h)(x) and (g+h)(x).

So, (g-h)(x) is given by

g(x)-h(x)\\\\=-4x+5-6x\\\\=-10x+5

and (g+h)(x) is given by

g(x)+h(x)\\\\=-4x+5+6x\\\\=2x+5

and (g-h)(3) is given by

-10(3)+5\\\\=-30+5\\\\=-25

Hence, our required values would be -10x+5, 2x+5 and -25.

5 0
3 years ago
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